All categories

2 years ago

y = x2 - 6x - 8 Complete the square in the quadratic equation in order to write the equation in vertex form.

Mathematics

1 answer:

Airida [17]2 years ago

8 0

Answer:

y = (x-3)^2 - 17

Step-by-step explanation:

To complete the square, take the middle term bx and divide it in two. Then take the square.

x^2 - 6x - 8 has bx = -6x. Take -6/2 = -3. Square -3^2 = 9.

Now to finish completing the square add 9 and subtract 9 from one side.

y = x^2 - 6x - 8

y = (x^2 - 6x +9) -9 - 8

y = (x-3)^2 - 17

You might be interested in

Long division 6 divided by 653

antoniya [11.8K]

Answer:

108.833

Step-by-step explanation:

I hope this helps :)

8 0

2 years ago

Read 2 more answers

Which equation has the solutions x=1+/- 5?

nikitadnepr [17]

Answer:

$x^{2} -2x-4=0$

Solving Steps

Use the quadratic formula

$x=\frac{-(-2)(+/-)\sqrt{(-2)^2-4*1*(-4)} }{2*1}$

Multiply / Remove the parentheses / Evaluate

$x=\frac{2(+/-)\sqrt{4+16} }{2}$

Calculate

$x=\frac{2(+/-)\sqrt{20} }{2}$

Separate the solutions

$x=\frac{2(+/-)2\sqrt{5} }{2} \\x=\frac{2-2\sqrt{5} }2}$

Simplify

$x=1+\sqrt{5} \\x=1-\sqrt{5}$

4 0

2 years ago

At a family reunion, each of Eddie's aunts and uncles is getting photographed once. The

sveticcg [70]

Answer:

Step-by-step explanation:

It will just be 12, since the uncles can go in one group and fit 12 uncles, and than the aunts can get photographed in 2 groups that add up to 12

4 0

2 years ago

Can somebody help me as soon as possible

QveST [7]

Answer:

It is A' B'

Pls give me brainliest :)

Step-by-step explanation:

5 0

1 year ago

Write and then solve for y = f(x) the differential equation for the statement: "The rate of change of y with respect to x is inv

vazorg [7]

The statement "<span>The rate of change of y with respect to x is inversely proportional to y^4" can be written mathematically as dy/dx = k/y^4

To solve the differential equation, we use variable saparable method.
y^4 dy = kdx
Integrating both sides gives,
y^5 / 5 = kx + A
y^5 = 5kx + 5A = Bx + C; where B = 5k and C = 5A
$y= \sqrt[5]{Bx+C}$ </span>

7 0

2 years ago