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Kipish [7]
3 years ago
5

What is the force on an object that goes from 35m/s to 85 m/s in 20 seconds and has a mass of 148kg?

Physics
1 answer:
Kipish [7]3 years ago
7 0
We will use Newton's second law to find the resultant force:
F = ma

For this, we need the acceleration given by:
a = (v - u) / t
a = (85 - 35) / 20
a = 2.5 m/s²

F = 148 x 2.5
F = 370 Newtons
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how much work does tension do on the laptop as it moves 2.0 mm ? express your answer with the appropriate units.
8090 [49]

The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J

W = F d cos θ

W = Work done

F = Force

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F = 14 N

d = 2 mm = 0.002 m

θ = 0

W = 14 * 0.002 * 1

W = 0.028 J

Work done is the change in energy of an object. So if an object moves a certain distance, work is done on the object. If the force and displacement are perpendicular to each other there is no work done on the object.

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8 0
1 year ago
A ball has a mass of 0.1 kg and an initial velocity of 20 m/s. The ball is given an acceleration of 30 m/s2 for 5 s. What is the
djverab [1.8K]

Answer:

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6 0
3 years ago
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A perfectly elastic collision occurs between a 15.0-kg mass traveling at 3.50 m/s and a 9.00-kg mass traveling at 2.35 m/s. if t
BaLLatris [955]
Momentum is conserved in a collision. Momentum is mass*velocity, so you can find your answer by calculating initial and final momentums and setting them equal to each other.

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3 years ago
when the mass of an object is increased it would decrease its acceleration in the force is left alone
mojhsa [17]

Answer:

See the explanation below.

Explanation:

This analysis can be easily deduced by means of Newton's second law which tells us that the sum of the forces or the total force on a body is equal to the product of mass by acceleration.

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where:

F = total force [N]

m = mass [kg]

a = acceleration [m/s²]

We must clear the acceleration value.

a=\frac{F}{m}

We see that the term of the mass is in the denominator, so that if the value of the mass is increased the acceleration decreases, since they are inversely proportional.

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