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IRISSAK [1]
3 years ago
5

If the vertical component of velocity for a projectile is 7.3 meters/second, find its hang time.

Physics
1 answer:
weqwewe [10]3 years ago
4 0
The height of the projectile is given by:
h = ut - 0.5at²

The height will be 0 twice, once at t = 0 and the second time at the time when the journey has been completed, or t = hang time.
0 = 7.3t - 0.5(9.81)t²
t = 1.49 seconds
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Why does the total amount of energy before and after<br> any energy transformations remain the same?
snow_tiger [21]

The Law of Conservation of Energy states that, in an isolated system, energy remains constant and can not be created or destroyed, only transferred from one form to another. This law was created by Julius Robert Mayer.

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3 years ago
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3) A dock worker pushes a 72 kg crate up a 2.0 m high,
Vlad [161]

Work done on the crate is 1411.2 J

Explanation:

Work done is defined as the product of force and the distance moved by the object. The unit of work done is in joules and denoted by the symbol J.

                                     Work done = F * d

where F represents the force and d represents the distance moved by the object.

mass = 72 kg , distance moved by the object is given by 2.0 m

Force F = mass * gravity = 72 * 9.8

             = 705.6 N =706 N.

Work done = 706 * 2.0 = 1412 J.

                   

7 0
3 years ago
PLLSSSS HELP<br> MARKING BRAINLIST<br> SCIENCE
Sveta_85 [38]

Answer:

the first one

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3 years ago
A horizontal force of 400.0 N is required to pull a 1760 N truck across the floor at a constant speed. Find the coefficient of s
Tomtit [17]

Data given:

Fh=400N

Ftruck=1760N

Data needed:

u=?

Formula needed:

Fh=Ftruck×u

Solution:

u=Fh/Ftruck

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4 0
3 years ago
Two moles of an ideal monatomic gas go through the cycle abc. For the complete cycle, 800 J of heat flows out of the gas. Proces
KiRa [710]

a) Sketches of all possible pv-diagrams for the cycle are attached below

b) The work W_{ac} for the process Ca is : 2462.8  J

<u>Given data :</u>

Amount of heat flowing out = 800 J

Ta = 200 K

Tb = 300 K

R = 800

<u>B) Determine the </u><u>work W </u><u>for the process</u><u> Ca</u><u> </u>

Wₐs = -pdv

       = - [ pVb - pVa ] ---- ( 1 )

note : pVb = nRTb ,  pVa = nRTa

Equation ( 1 ) becomes

= -nR [ Tb - Ta ]

= - 2(8.314 ) [ 300 - 200 ]

= - 1662.87

given that W_{bs} = 0 which is isochonic

dv = 0 ( cyclic process ) = d∅ - dw

∴ 0 = 800 - ( Wₐs  +  W_{ac} )

Therefore : W_{ac} = 800 + 1662.8 = 2462.8  J

Hence we can conclude that the work W for the process Ca = 2462.8  J

Learn more about Pv diagrams : brainly.com/question/25401637

Download pdf
3 0
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