Answer:
Step-by-step explanation:
Let the volume of tank be x
In 18 hours volume of tank filled = x
we have to find the volume of tank which is filled in 1 hours.
For that we divide LHS and RHS by 18
In 18/18 hours volume of tank filled = x/18
In 1 hours volume of tank filled = x/18
In 30 hours volume of tank emptied = x
we have to find the volume of tank which is emptied in 1 hours.
For that we divide LHS and RHS by 30
in 30/30 hours volume of tank filled = x/30
In 1 hours volume of tank filled = x/30
If tank is empty and one starts to fill it, two things will happen
it will start filling at rate of x/18 hours
But there is leak which will start to empty the tank at x/30 hours
So , at any given time rate if filling of water will be rate of filling the tank- rate of emptying the tank
In 1 hour volume of tank filled if both filling and leaking takes place simultaneously = x/18 -x/30 = (30-18)x/18*30 = 12x/18*30 = x/3*15 = x/45
In 1 hour volume of tank filled = x/45
in 1*45 hour volume of tank filled = x/45*45 = x
Thus, it will take 45 hours to fill the leaky tank .
