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2 years ago

Complete the function table for each equation

Mathematics

1 answer:

I am Lyosha [343]2 years ago

7 0

Answer:

y=-32, 0, -16, -4, 16

Step-by-step explanation:

y=4(-6)-8= -32

y=4(2)-8 = 0

y=4(-2)-8 = -16

y=4(1) -8 = -4

y=4(6) -8= 16

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3 years ago

A book falls from a shelf that is 5 feet above the floor. A model for the height h in feet if an object dropped from an initial

Brums [2.3K]

Answer:

About 0.559 seconds

Step-by-step explanation:

The height equation is:

$h=-16t^2+h_0$

Where $h_0$ is the initial height of the book, which is 5, so we can write:

$h=-16t^2+5$

Now, we want time it took for the book to reach ground (h = 0)

So, we substitute h = 0 and solve for t:

$h=-16t^2+5\\0=-16t^2+5\\16t^2=5\\t^2=0.3125\\t=0.5590\\t=0.559$

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3 years ago

Predicting the next item in a pattern is an example of inductive reasoning? True or false

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Step-by-step explanation:

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3 years ago

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erastovalidia [21]

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Step-by-step explanation:

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2 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable X represent the time a child spends waiting at for the bus as a school bus stop.

The random variable X is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of X is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

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2 years ago