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katrin [286]
3 years ago
8

A circle has a circumference of 7,850 units. What is the radius of the circle?

Mathematics
1 answer:
ioda3 years ago
8 0

Answer:1250 units

Step-by-step explanation:

circumference=7850

Radius=?

Radius=circumference ➗ (2xπ)

Radius=7850 ➗ (2 x 3.14)

Radius=7850 ➗ (6.28)

Radius=1250 units

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A colony of 85 bacteria doubles in size every 126 minutes. What will the population be 378
SVETLANKA909090 [29]

Answer:

680 Bacteria

Step-by-step explanation:

378 is evenly divisible by 126, which is equal to 3.

The first 126 minutes, the 85 bacteria will double to 170 bacteria.

The second 126 minutes (252 minutes total), the 170 bacteria will double to 340 bacteria.

The final 126 minutes (378 minutes total), the 340 bacteria will double to 680 bacteria total.

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6 0
3 years ago
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Find the 23rd sequence out of 3 5 7 9 11
Licemer1 [7]
The answer is 47 because  3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47

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Find the area of the triangle. Figure is not drawn to scale. Show your work. (Image attached)
Zolol [24]

Answer: 13.8cm^2

Step-by-step explanation:

The area of a triangle can be calculated with the formula:

A_{(triangle)}=\frac{b*h}{2}

The base of the triangle is "b" and the height of the triangle is "h",

In the figure you can observe that the base and the height of the triangle are:

b=6.9cm\\h=4cm

Knowing these values, you can substitute them into A_{(triangle)}=\frac{b*h}{2}.

Therefore, the area of the triangle is:

A_{(triangle)}=\frac{(6.9cm)(4cm)}{2}

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4 0
3 years ago
What is the area of a circle if the circumference is 29
Kruka [31]

Answer:

67 square units

Step-by-step explanation:

Circumference/pi = diameter

29/3.14 = 9.24

Radius = 9.24/2 = 4.62

A = pi * r^2

A = 3.14 * 4.62^2 = 67 square units

8 0
2 years ago
PLEASE PLEASE HELP! Find the measure of APB^.
Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

\angle CAT=\angle CBT=90^{\circ}

Since angle BAT is equal to 65°, angle CAB has measure

\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

\angle CBA=\angle CAB=25^{\circ}

The sum of the measures of all interior angles in triangle is always 180°, so

\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}

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x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}

8 0
3 years ago
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