Which ordered pair makes both inequalities true? y > –2x + 3 y < x – 2 (0,0) (0,–1) (1,1) (3,0)

Mathematics

2 answers:

gregori [183]3 years ago

8 0

Answer:

(3,0)

Step-by-step explanation:

Given system of inequalities,

y > -2x + 3

y < x - 2

At (0,0),

0 > -2(0) + 3 ( False )

0 < 0 - 2 ( False )

At (0, -1),

- 1 > -2(0) + 3 ( False )

-1 < 0 - 2 ( False )

At (1, 1),

1 > -2(1) + 3 ( False )

1 < 1 - 2 ( False )

At (3, 0),

0 > -2(3) + 3 ( True )

0 < 3 - 2 ( True )

Hence, the order pair (3, 0) makes both inequalities true.

Last option is correct.

m_a_m_a [10]3 years ago

7 0

The answer is (3,0).

You might be interested in

Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel

timama [110]

Answer:

$\displaystyle A=\frac{1}{192}$

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

$P=4x+3y$