Answer:
See explanation
Step-by-step explanation:
In the figure below, segment CD is parallel to segment EF, DE is a transversal, then angles DIH and HGI are congruent as alternate interior angles when two parallel lines are cut by a transversal.
Consider triangles DIH and EGH. In these triangles,
as alternate interior angles;
as vertical angles;
because point H bisects segment DE (given).
Thus,
by AAS postulate
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Answer:
I'm newbie here
Step-by-step explanation:
Elimination Method.
4x + 6/y = 15 → step 1
6x - 8/y = 14 → step 2
so,
4x + 6/y = 15 |×6|
6x - 8/y = 14 |×4|
24x + 6/y(6) = 90
24x - 8/y(4) = 56
24x + 36/y = 90
24x - 32/y = 56
____________ _
68/y = 34
68 = 34y
34y = 68
y = 2
subsitution y = 2 to..
4x + 6/y = 15
4x + 6/2 = 15
4x + 3 = 15
4x = 12
x = 3
So, for x is 3, and for y is 2
Answer:
D) 25π/2 in²
Step-by-step explanation:
The area of a sector of central angle θ and radius r is ...
... A = (1/2)r²θ
Your sector has central angle π/4 and radius 10 in, so has area ...
... A = (1/2)(10 in)²(π/4)
... A = 25π/2 in² . . . . matches selection D
