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Lina20 [59]
3 years ago
15

Please help !! :)

Mathematics
2 answers:
UkoKoshka [18]3 years ago
5 0
I believe the answer to this is 12 inches.
kari74 [83]3 years ago
4 0

Answer:D: 12

Step-by-step explanation:

D) The sum of any two sides of a triangle must be greater than the third side.

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Can someone please help me?
Nesterboy [21]

Answer:

2

Step-by-step explanation:

i dont know

8 0
2 years ago
I BEGGG U TO HELP Me PLZZ ITS tESt<br> I WILl GiVE U BRAINLIESTTTT),:
ZanzabumX [31]

Answer:

C. 2/3

Step-by-step explanation:

5 0
3 years ago
Linear Programming:
tatuchka [14]
Let the number of large bookcases be x and number of small bookcases be y, then
Maximise P = 80x + 50y;
subkect to:
6x + 2y ≤ 24
x, y ≥ 2

The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67

Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
7 0
3 years ago
Given that €1=£0.72 how much is €410 in £ what is the £ to € exchange rate
Virty [35]

Answer:

As per the given statement:

€1 = £0.72

Find how much is €410 in £.

then;

€410 = 0.72 \times 410 = £295.2

Hence, £295.2 much is €410.

to find, the exchange rate of £ to €:

€1 = £0.72

Divide both sides by 0.72 we get;

£1 = €1.389

4 0
3 years ago
A car braked with a constant deceleration of 16ft/s2, producing skid marks measuring 200 feet before coming to a stop. How fast
Llana [10]

Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.

Step-by-step explanation:

The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,

a = - 16ft/s^2

While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.

This means that it travelled a distance,

s = 200 feet

We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.

Since the car came to a stop, its final velocity, v = 0

Applying Newton's equation of motion,

v^2 = u^2 + 2as

0 = u^2 - 2 × 16 × 200

u^2 = 6400

u = √6400

u = 80 ft/s

7 0
3 years ago
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