Question

A rifle is fired straight up, and the bullet leaves the rifle with an initial velocity magnitude of 724 m/s. After 5.00 s the velocity is 675 m/s. At what rate is the bullet decelerated?

Answer 1

v (final) = v (initial) + at

675 = 724 + a (5.00)

a = -9.8 m/s^2

negative is simply mean decelerate, therefore, the answer would be 9.8 m/s^2