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Nadya [2.5K]
2 years ago
15

How many points out of 416 do i need to get to get a 60% in class Right now I have 153.

Mathematics
2 answers:
My name is Ann [436]2 years ago
5 0

You currently have a 36%.

You need 249-250% to get a 60% in your class.

Best of luck!

xeze [42]2 years ago
3 0

Answer: 249.6 so 250

Step-by-step explanation: Take 416 times it by 0.6 Have a nice day. Hope it helped!

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paul can finish painting a fence in 2 hours if jane douse the job alone she can finish it in 5 hours how long will it take them
NeTakaya

Answer: 40 minutes

Step-by-step explanation:

2/5 = .4 so it would be 40 minutes

4 0
2 years ago
The two largest lizards in the United States are the Gila monster and the chuckwalla. The average Gila monster is 0.608 meter lo
Zanzabum

Answer:

1.54 to the nearest hundredth

Step-by-step explanation:

Divide the average length of a Gila lizard by length of a chuckwalla.

= 0.608 / 395

4 0
3 years ago
....Help Please......
Bogdan [553]

Answer:

9984000

Step-by-step explanation:

subtract the total by the other number (coverage)

3 0
2 years ago
Read 2 more answers
PLEASE HELP I CANT CONTINUE WITH MY WORK UNLESS THESE ARE COMPLETE AND CORRECT
Snezhnost [94]

Answer:

1) x=3, y=-3

Step-by-step explanation:

10x + 7y = 9 —— (1)

-4x -7y = 9 —— (2)

(1) + (2)

6x = 18

x = 18/6

x = 3

put x=3 in (1)

10(3) + 7y = 9

30 + 7y = 9

7y = 9 - 30

7y = -21

y = -21/7

y = -3

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6 0
3 years ago
A printer has a contract to print 100,000 posters for a political candidate. He can run the posters by using any number of plate
yulyashka [42]

Answer:

25

Step-by-step explanation:

From the given information;

Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.

= 1000x

Thus, the required number of hours it will take can be computed as:

\implies \dfrac{100000}{1000x} \\ \\ =\dfrac{100}{x}

cost per hour = 125

If each plate costs $20 to make, then the total number of plate will equal to 40x

∴

The total cost can be computed as:

C(x) = (\dfrac{100}{x}) \times 125 + 20 x --- (1)

C'(x) = (-\dfrac{12500}{x^2})  + 20  --- (2)

At C'(x) = 0

\dfrac{12500}{x^2} = 20

\dfrac{12500}{20} = x^2

x^2= 625

x = \sqrt{625}

x = 25

C'' (x) = -12500 \times \dfrac{-2}{x^3} +0

C'' (x) = \dfrac{25000}{x^3}

where; x = 25

C'' (x) = \dfrac{25000}{25^3}

C''(x) = 1.6

Thus, at x = 25, C'' > 0

As such, to minimize the cost, the printer needs to make 25 metal plates.

4 0
3 years ago
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