Answer:
- The initial value corresponds to the y value when x = 0
Step-by-step explanation:
Since the graph is given, it is unnecessary to "finish the line." It is only necessary to read the value of y from the graph where x=0.
Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x
Answer:
First term (a) =8
Common difference (d)= t2-t1
=12-8
=4
Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}
= 31/2{2×8+(31-1)4}
=31/2{16+(30×4)
=31/2(16+120)
=31/2×126
=31×63
Step-by-step explanation:
Similarly use 19 as (n) for the 19th term
Answer:
After Two Hours.
Step-by-step explanation:
A simple way to do it is to:
1. Add 50+55, it is equal to 105. This is after one hour, so we know that it's more than this.
2. Add 50+55 to 105, This is after two hours, and we get 210, so we know that it has to be equal to 2 hours.
Answer:
(x-5)²+(y-7)²=80
Step-by-step explanation:
