Question

Please help ASAP I will make you brainiest- I need this dont in the next hour!!

Answer 1

Answer:

x ≥ 661.424°F or x[661.424,∞) and x ≤ - 27°F or x(-∞,-27]

Step-by-step explanation:

The melting point of the substance is - 32.78°C, then the melting point in °F is given by  

$C = \frac{5}{9} (F - 32)$

⇒ $F - 32 = \frac{9}{5}C$

⇒ $F = 32 + \frac{9}{5} (-32.78)$

⇒ F = - 27.004°F

Again, the boiling point of the substance is 349.68°C, hence, the boiling point in °F is  

$F = 32 + \frac{9}{5} (349.68)$

⇒ F = 661.424°F

Therefore, the range of temperature in °F for which the substance will not be in liquid state will be x ≥ 661.424°F or x[661.424,∞) and x ≤ - 27.004°F or x(-∞,-27.004], where x is the temperature of the substance in °F. (Answer)