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2 years ago

Figure P, the small rectangle, was dilated with the origin as the center of dilation to create Figure Q, the large rectangle.

Mathematics

2 answers:

Anarel [89]2 years ago

8 0

Jrnkijhhhgrefgbtrrtghhkg

yKpoI14uk [10]2 years ago

4 0

Answer:

rule: four times longer and four times wider!

Step-by-step explanation:

since the length of figure Q is 4 times than figure P the width of figure Q is 4 times than figure P. so the figure p is enlarged by 4 times in all.

so the rule is stretching four times in length and in width!

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6 1/4 minus 3 5/8 please answer this please

barxatty [35]

6-3=3
2/8-5/8=3/8
you would have to change the denominator

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3 years ago

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1. Approximate the value of √ √

MAVERICK [17]

Answer:

$\sqrt{3} =1.7\\\sqrt{3/48} =0.04\\\sqrt{48} =6.9\\\frac{\sqrt{3} }{\sqrt{48} } =0.25$

Step-by-step explanation:

I wasn't sure which one you were referring to

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2 years ago

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Mars2501 [29]

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2 years ago

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\int\limits^0_∞ cos{x} \, dx

JulijaS [17]

Answer:

$\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty)$

General Formulas and Concepts:

Pre-Calculus

Unit Circle
Trig Graphs

Calculus

Limits
Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$
Integrals
Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$
Trig Integration
Improper Integrals

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int\limits^0_\infty {cos(x)} \, dx$

Step 2: Integrate

[Improper Integral] Rewrite: $\displaystyle \lim_{a \to \infty} \int\limits^0_a {cos(x)} \, dx$
[Integral] Trig Integration: $\displaystyle \lim_{a \to \infty} sin(x) \bigg| \limits^0_a$
[Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle \lim_{a \to \infty} sin(0) - sin(a)$
Evaluate trig: $\displaystyle \lim_{a \to \infty} -sin(a)$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle -sin(\infty)$

Since we are dealing with infinity of functions, we can do a numerous amount of things:

Since -sin(x) is a shift from the parent graph sin(x), we can say that -sin(∞) = sin(∞) since sin(x) is an oscillating graph. The values of -sin(x) already have values in sin(x).
Since sin(x) is an oscillating graph, we can also say that the integral actually equates to undefined, since it will never reach 1 certain value.

∴ $\displaystyle \int\limits^0_\infty {cos(x)} \, dx = sin(\infty) \ or \ \text{unde}\text{fined}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Improper Integrals

Book: College Calculus 10e

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3 years ago

May someone help me out with this question please

mario62 [17]

You would have 60 different types of pens with this brand. You need to multiply 12 and 5 (because you have 12 different colors for every type of tip, so you have 5 groups of 12).

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3 years ago