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2 years ago

7

How can systems of linear equations with two variables be solved using algebraic methods?

1 answer:

erik [133]2 years ago

8 0

Answer: The systems are solved by solving for one variable in one of the equations, then substituting that equation into the second equation. Solve for a in the second equation, then substitute the second equation into the first. The Elimination Method: Both equations are in standard form: Ax + By = C.

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Simplify and write the complex number in standard form 4i(7+6i)+2i(5-2i)

Bezzdna [24]

Answer:

20i² + 38i

Step-by-step explanation:

4i(7+6i)+2i(5-2i)

28i + 24i² + 10i - 4i²

24i² - 4i² + 28i + 10i

20i² + 38i

3 0

2 years ago

Read 2 more answers

How are the values of -4^3 and 4^-3 alike and how do they differ?

BartSMP [9]

Answer:

(-4)³ = -64

(4)⁻³ = 1/64

Step-by-step explanation:

$( - 4) {}^{3} = ( - 4) \times ( - 4) \times ( - 4) = - 64 \\$

${4}^{ - 3} = (\frac{1}{4} ) {}^{3} \\$

$({ \frac{1}{4} )}^{3} = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = \frac{1}{64} \\$

4 0

1 year ago

A music sharing service has an initial fee of $25 and a monthly fee of $6. When a person joins the service, it costs the company

STALIN [3.7K]

Answer: $25+6m > 70$

Step-by-step explanation:

Let m = Number of months

Combined charges for music sharing service = 25+6m

Cost of joining to company = $70

According to the question,

Combined charges > Cost of joining to company (To find number of months it would take for this)

$25+6m > 70$ (required inequality)

3 0

2 years ago

The widths of two similar rectangles are 10 m and 15 m. What is the ratio of the perimeters? Of the areas?

vitfil [10]

Area and perimeter are in the ratio of 1:3. but if u mean to ask about the ratio of perimeters & areas of both triangles. the answer would be 1:1

6 0

2 years ago

mafiozo [28]

Answer:

(2) x2+1+4/x+2

Step-by-step explanation:

I hope i am right sorry if i am wrong.

4 0

2 years ago