Answer:
The rule or operation in this sequence is multiplication by 3.
Step-by-step explanation:
2*3=6
6*3=18
18*3=54
and so on...
Answer: 1/6
Step-by-step explanation:
A die has 6 numbers which are 1, 2, 3, 4, 5 and 6.
Odd numbers in a die = 1, 3 and 6
Numbers greater than 4 = 5 and 6
Probability of rolling an odd number = 3/6 = 1/2
Probability of rolling a number greater than 4 = 2/6 = 1/3
We then multiply both values gotten. This will be:
= 1/2 × 1/3
= 1/6
Therefore, the probability of rolling an odd number the first time and a number greater than 4 the second time is 1/6.
Answer:
(a) The ones that are equivalent to the given fraction are:
and 
(b) The one that is equivalent to the given fraction is:
Answer:
I don't know what kind of questions is this but first you need to show your spinner
Answer:
a. A(x) = (1/2)x(9 -x^2)
b. x > 0 . . . or . . . 0 < x < 3 (see below)
c. A(2) = 5
d. x = √3; A(√3) = 3√3
Step-by-step explanation:
a. The area is computed in the usual way, as half the product of the base and height of the triangle. Here, the base is x, and the height is y, so the area is ...
A(x) = (1/2)(x)(y)
A(x) = (1/2)(x)(9-x^2)
__
b. The problem statement defines two of the triangle vertices only for x > 0. However, we note that for x > 3, the y-coordinate of one of the vertices is negative. Straightforward application of the area formula in Part A will result in negative areas for x > 3, so a reasonable domain might be (0, 3).
On the other hand, the geometrical concept of a line segment and of a triangle does not admit negative line lengths. Hence the area for a triangle with its vertex below the x-axis (green in the figure) will also be considered to be positive. In that event, the domain of A(x) = (1/2)(x)|9 -x^2| will be (0, ∞).
__
c. A(2) = (1/2)(2)(9 -2^2) = 5
The area is 5 when x=2.
__
d. On the interval (0, 3), the value of x that maximizes area is x=√3. If we consider the domain to be all positive real numbers, then there is no maximum area (blue dashed curve on the graph).