5 times 7/8 then converted to simplest form?

1 answer:

7 0

5*7/8 = 4 3/8
5/1 * 7/8 = 35/8
convert into mixed number because numerator is bigger than the denominator so it it
4 3/8

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Use synthetic division to determine if x+2 is a factor of f(x)=5x2+13x+6

Karolina [17]

Answer:

x+2 is a factor of $f(x) = 5x^2 + 13x + 6$

Step-by-step explanation:

To check: If (x+2) is a a factor of the polynomial $f(x) = 5x^2 + 13x + 6$

We need to check if x = -2 is the FACTOR of the given polynomial.

⇒ To show: f (-2) = 0

Now

$f(-2) = 5(-2)^2 + 13(-2) + 6\\=5(4) -26 + 6\\= 20 + 6 - 26\\= 26 - 26 = 0\\\implies f(-2) = 0$

Since, f(-2) = 0

⇒ -2 is the ROOT of the Polynomial f(x).

⇒(x +2) is the factor of the given polynomial.

Hence, x+2 is a factor of $f(x) = 5x^2 + 13x + 6$

4 0

3 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$