The are 4 different possibilities to draw a ten, namely a ten of the four different suits. The probability of the event is the ratio of the 4 possibilities and the total number of possible choices, whcih is 52:
P(E) = 4/52 = 1/13 or about 7.7%
Answer:
The second one is right
Step-by-step explanation:
Hope it helpssss
B is your answer because if u look at it the
Use BODMAS or BIDMAS (Brackets, over Indices, Division, Multiplication, Addition, the Subtraction, this tells you which order to do things in)
As you cant do √10 in the brackets you do the indices, so (√10)³
Split this up to make it easier
(√10)³= √10 x √10 x √10 = 10√10
You the multiply this by 9
9 x 10√10 = 90√10
then multiply by 5
5 x 90√10 = 450√10 = 1423.024947 (using calculator)
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k