A subtraction problem can be turned in to an addition problem because of negative numbers. Take 5-2=3 for example. If you change 5-2 into an addition problem then you would but he addition sign and a negative sign on 2. This will then leave you with the problem looking like 5+ -2. If you add 5 and -2 you will still get three.
The answer is infinitely many solutions because 0 = 0.
If you don't seem to see where I got 0 = 0, look at the equation,
4b – 4b = 0
first lets do the math on the left side.
4b - 4b is equal to 0.
so lets put 0 on the left side, now lets look at the equation all together,
0 = 0,
and this means that it has infinitely many solutions.
The reason why it is not no solution because no solution means when there are no answers to the equation. For example, the solution is not true, such as the equation 24 ≠ 29. This is a no solution equation. One solution can be 4x = 20, as x = 5, concluding it being one solutions.
My friend... My method wasn't wrong and I couldn't find any mistake on my procedure... Check it out and analyze it by yourself...
Answer:
Vamos a inventa tres multiplicaciones de seis factores en la que el resultado sea positivo, es decir un número mayor que cero, en la otra negativo, es decir, un número menor que cero y por último otra multiplicación que de como resultado el cero "0".
Primero recordemos que:
Los factores son los números que se multiplican.
Seis factores serían 6 números.
Multiplicación con resultado positivo, es decir mayor a 0:
2×3×4×2×1×5=240
Multiplicación con resultado negativo, es decir menor a 0:
-4×2×5×2×1×10= -400
Multiplicación con resultado cero:
2×4×6×7×11×0=0
Step-by-step explanation:
Brainliest please
Answer:
Step-by-step explanation:
Given that the number of children in a household has a binomial distribution with parameters n-8 and p-50%
As per binomial definition we have
=
a) P(x=3 or 7) = P(3)+P(7) = 0.2188+0.0313=0.2501
b) P(X≤5)=0.8555
c) P(X≥3)=0.8555
d) P(x<7) =0.9648
