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nydimaria [60]
2 years ago
10

END OF THE YEAR QUIZ PLEASE ANSWER ( question Is shown in photo)

Mathematics
2 answers:
Feliz [49]2 years ago
4 0

Answer:

Answer is C

Step-by-step explanation:

Using pythagoras theorem,

h^2=p^2+b^2

(root under 32)^2=(4)^2+(4)^2

(root under 32)^2=16+16

Therefore,h^2=p^2+b^2....

Would you please mark my answer the brainliest:)

lana66690 [7]2 years ago
3 0

Answer:

B

Step-by-step explanation:

if you move the decimal over one you get 15 20 25. If you divide all of them by 5 you get 3 4 5. which is a right triangle.

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What is cd? please answer
stealth61 [152]

Answer:

18 units

Step-by-step explanation:

The centroid is located 1/3 the distance from the midpoint of a side to the opposite vertex. That means ...

CG = 2·DG = 6 + DG

Then

DG = 6 . . . . . . subtract DG from the above equation

Of course, ...

CD = CG +DG = 2·6 +6

CD = 18

7 0
3 years ago
HELP ASAP PLZ IM TIMED
nasty-shy [4]

Answer:

70

Step-by-step explanation:

4 0
2 years ago
Samira needs 22 quarts of lemonade to fill a dispenser. She plans to buy 7 jugs of lemonade. Each jug contains 3.3 quarts. Is th
GarryVolchara [31]

Answer:

i just took the test the answer is yes i did not know that

Step-by-step explanation:

it is responsible

<h2>rip  </h2><h3>plz make brainlyest</h3><h3 />
7 0
3 years ago
What is the volume of the triangular prism below?
worty [1.4K]

Answer:

4.5 ft

Step-by-step explanation:

18 inches = 1.5 ft

\frac{1}{2}  \times 1.5 \times 2 \times 3 = 4.5

Volume of triangular prism = Base Area x Length

Hope this helps

8 0
3 years ago
Let the smallest of 4 consecutive odd numbers be 2 n + 1 , where n is an integer. Show, using algebra, that the sum of any 4 con
andrey2020 [161]

Answer:

Expression is 8(n+2)

Step-by-step explanation:

smallest of 4 consecutive odd numbers =2n + 1

consecutive odd integers are found by adding 2 to the any given odd numbers

Thus, 2nd consecutive odd integers  = 2n + 1 + 2 = 2n + 3

3rd consecutive odd integers  = 2n + 3 + 2 = 2n + 5

2nd consecutive odd integers  = 2n + 5 + 2 = 2n + 7

Thus, 4 consecutive odd integers are

2n + 1 ,2n + 3,2n + 5,2n + 7

sum of these numbers are = 2n + 1 +2n + 3 + 2n + 5+2n + 7 = 8n+16

sum of these numbers are = 8(n+2)

Thus, we see that the sum of numbers are 8(n+2)

As, 8 is common for n+2, whatever is value of n, the number will be multiple of 8 .

thus expression is 8(n+2)

7 0
3 years ago
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