We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.
Answer:
5.5 = 5.5 = 55 1/2
6.5 = 6.5 = 66 1/2
Step-by-step explanation:
<span> Given polynomial x^2+8x-48 = 0</span>
<span>x^2+12x-4x-48 = 0</span>
<span>x(x+12)-4(x+12) = 0</span>
<span>(x+12)(x-4) = 0</span>
<span>x+12 = 0</span>
Subtract 12 from each side.
<span>x+12-12 = 0-12</span>
<span>x = -12</span>
<span>and x-4 = 0</span>
Add 4 to each side.
<span>x-4+4 = 0+4</span>
<span>x = 4</span>
<span>Roots are -12,4.</span>
Answer:
3x² + 30x
Step-by-step explanation:
width of a box = x units.
height of a box = 3 units.
length of a box = (x + 10) units.
Volume of the box = length × width × height
= (x + 10) * x * 3
= (x + 10) * 3x
= 3x² + 30x
Volume of the box = 3x² + 30x
Whats the choices?..............................................................................
