Question

A tour boat left the dock and traveled west at an average speed of 10 mph. A smaller fishing boat left some time later traveling in the same direction but at an average speed of 12 mph. After traveling for 10 hours, the fishing boat caught up to the tour boat. The tour boat left _______ hours earlier than the fishing boat.
A. 2
B. 11
C. 10
D. 18

Answer 1

Answer:

avagorman20 you are really close but the actual answer is A. 2

Bc  so first of all if we check all the numbers that are given to us we could see that the first boat goes 10 mph sometime later the 12 mph boat goes off and travels for 10 hours then catches up to the other boat.

Im not a pro at equations but I do know how to do some mental math:

12 x 10 = 120 (second boat) that means that the first boat 10 x 10= 100 drove out 2 hours earlier 10 mph + 2 hours = 12mph, and that is how much the other boat is going... kinda confusing but idk how to explain in other ways  

Answer 2

Answer:

The answer is D.

Step-by-step explanation:

Time = Distance / Speed

Distance = 12 *10 =120

Time = 120 / 12

Time = 10

Please correct if me if I'm wrong