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3 years ago

if the chromosome number in the sporophyte generation of a plant is 32 what is its number in the gametophyte generation?

1 answer:

3 0

Chromosomes have hereditary function that are capable of self-duplication and they have thread-like structures seen inside the nucleus of plant and animal. In plants, they go through a cycle called alteration of generation that has multicellular stages. One is sporophyte that is a diploid, and the other is gametophyte with a haploid.

<span>Moreover, spores are produce through meiosis so it go through a process of chromosome reduction in order to create a haploid spores. While, gametes undergo mitosis and the structure is already a haploid, which means that the number of chromosomes will not change in order to produce haploid. In this case, the plant have both spores and gametes and the similarities is that, they are both singles celled and a haploid. Therefore, the number of the chromosome in the gametophyte generation is also 32.</span>

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4 years ago

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In one of his experiments, Lavoisier placed 10.0 grams of mercury (II) oxide into a sealed container and heated it. The mercury

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Oxygen gas produced : 0.7 g

<h3>Further explanation</h3>

Given

10.0 grams HgO

9.3 grams Hg

Required

Oxygen gas produced

Solution

Reaction⇒Decomposition

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3 years ago

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3 years ago

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a gas in a container with a fixed volume was originally at a pressure of 317kpa and a temperature of 154k. what is the new press

goldfiish [28.3K]

<h2>Hello!</h2>

The answer is: 4.77atm

Since there's a fixed volume, we can use the the Gay-Lussac's Law which stablish a relation between the pressure and the temperature:

$\frac{P}{T}=k$

<em>P</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

We also have the following equation:

$\frac{P1}{T1}=\frac{P2}{T2}$

Where:

$P2=\frac{P1*T2}{T1}=\frac{317kPa*235K}{154K}=483.73kPa$

We are asked to find the pressure in atm, so we must convert 483.73kPa to atm:

$1kPa=0.009869atm$

Then,

$483.733kPa*\frac{0.009869atm}{1kPa}=4.77atm$

Have a nice day!

8 0

4 years ago

What’s the answer ?

Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

6 0

3 years ago