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vodka [1.7K]
3 years ago
13

During an experiment, some water was removed from each of the 6 water tanks. If the standard deviation of the volumes of water i

n the tanks at the beginning of the experiment was 10 gallons, what was the standard deviation of the volumes of water in the tanks at the end of the experiment?
(1) For each tank, 30% of the volume of water that was in the tank at the beginning of the experiment was removed during the experiment.
(2) The average (arithmetic mean) volume of water in the tanks at the end of the experiment was 63 gallons.
Mathematics
1 answer:
Julli [10]3 years ago
6 0

Answer:

First statement is correct.

Step-by-step explanation:

If we add or subtract a constant to each term in a set:  Mean will increase or decrease by the same constant.  Standard Deviation will not change.

If we increase or decrease each term in a set by the same percent (multiply all terms by the constant):  Mean will increase or decrease by the same percent.  Standard Deviation will increase or decrease by the same percent.

For example:

Standard Deviation of a set: {1,1,4} will be the same as that of {5,5,8} as second set is obtained by adding 4 to each term of the first set.

That's because Standard Deviation shows how much variation there is from the mean. And when adding or subtracting a constant to each term we are shifting the mean of the set by this constant (mean will increase or decrease by the same constant) but the variation from the mean remains the same as all terms are also shifted by the same constant.

So according to this rule, statement (1) is sufficient to get new Standard Deviation, it'll be 30% less than the old.. As for statement (2) it's clearly insufficient as knowing mean gives us no help in getting new Standard Deviation.

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Gre4nikov [31]

Answer: total profit = $418

======================================================

Work Shown:

June

Income = (4 lawns)*($27 per lawn) = $108

Expenses = ($32 for gas)+($12 for trim line) = $44

Profit = income - expenses = 108-44 = $64

----------------------------

July

Income = (12 lawns)*($20 per lawn) = $240

Expenses = ($89 for gas)+($29 for blade sharpening) = $118

Profit = income - expenses = 240 - 89 = $151

----------------------------

August

Income = (16 lawns)*($20 per lawn) = $320

Expenses = ($101 for gas)+($16 for oil) = $117

Profit = income - expenses = 320-117 = $203

----------------------------

Total profit = (june profit)+(july profit)+(august profit)

Total profit = (64) + (151) + (203)

Total profit = $418

If the final result was negative, then we would call this a loss. However, we have a positive value, so we go with a profit.

8 0
3 years ago
In the equation y = -6x + 2, what is the value of slope?<br> 25 Points!!!!!!!
zepelin [54]

Answer:

-6

Step-by-step explanation:

In y = mx + c,

m is the slope

y = -6x + 2

m = -6

5 0
3 years ago
Read 2 more answers
Please answer correctly! I will mark you as Brainliest!
alukav5142 [94]

Answer:

1024pi/3

Step-by-step explanation:

to find the volume of a sphere you use the equation 4/3*pi*r^3

4/3*pi*8^3

4/3*pi*512

2048/3 pi

This is the volume of the whole sphere but we only need half so we can just divide by 2.

(2048/3 pi)/2

1024/3 pi

6 0
3 years ago
Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12
tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12

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Need help ASAP.picture provides question
OLga [1]

Answer:

p=12-7/x

Step-by-step explanation:

thats what p(2)is

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