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Zina [86]
3 years ago
14

Please help me thank u❤️

Chemistry
2 answers:
andre [41]3 years ago
6 0

Answer:

chemcial energy :)

Explanation:

Alex73 [517]3 years ago
5 0

Answer:

at the light = radiant energy

at the line = electical energy

at the battery = chemical energy

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At a certain temperature, 0.800 mol SO 3 is placed in a 1.50 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil
Elanso [62]

Answer : The value of equilibrium constant (K) is, 0.004

Explanation :

First we have to calculate the concentration of SO_3\text{ and }O_2

\text{Concentration of }SO_3=\frac{\text{Moles of }SO_3}{\text{Volume of solution}}=\frac{0.800mol}{1.50L}=1.2M

and,

\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{0.150mol}{1.50L}=0.1M

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

                       2SO_3(g)\rightarrow 2SO_2(g)+O_2(g)

Initial conc.       1.2             0               0

At eqm.          (1.2-2x)        2x               x

As we are given:

Concentration of O_2 at equilibrium = x = 0.1 M

The expression for equilibrium constant is:

K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}

Now put all the given values in this expression, we get:

K_c=\frac{(2x)^2\times (x)}{(1.2-2x)^2}

K_c=\frac{(2\times 0.1)^2\times (0.1)}{(1.2-2\times 0.1)^2}

K_c=0.004

Thus, the value of equilibrium constant (K) is, 0.004

3 0
4 years ago
How do i know if a reaction is exo/endothermic?? help please.
goblinko [34]

Answer:

Explanation: in exothermic reaction heat is released out

In endothermic reaction heat is absorbed

3 0
3 years ago
PLEASE HELP!!!!
shtirl [24]
1) d

2) b because the independent variable is the thing you change/control in an experiment

3) c because the dependent variable is the thing being measured in an experiment

4)hmm it might be d, as c and a are both correct as different sized feeders would make it an unfair test and different types of food would as well

5) c

6) a

7) b obviously because if he activated them at different times then the ones activated last would have an advantage

6 0
4 years ago
How much hear must be obsorberd by 375.0 grams of water to raise its temperature from 10.0c to 35.0c? The specific heat capacity
inysia [295]

Answer:

The heat absorbed by water is 39243.75 J.

Explanation:

Given data:

Mass of water = 375.0 g

Heat absorbed by water= ?

Initial temperature = 10.0°C

Final temperature = 35.0 °C

The specific heat capacity of water = 4.186 j/g.°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 35°C - 10°C

ΔT = 25°C

Q = m.c. ΔT

Q = 375.0 g× 4.186 j/g °C × 25°C

Q = 39243.75 J

The heat absorbed by water is 39243.75 J.

3 0
3 years ago
What will happen if we burn carbon monoxide In a closed room??
Marianna [84]

Answer:

the carbon monoxide will release blue fumes

7 0
3 years ago
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