Answer : The value of equilibrium constant (K) is, 0.004
Explanation :
First we have to calculate the concentration of 
and,
Now we have to calculate the value of equilibrium constant (K).
The given chemical reaction is:
Initial conc. 1.2 0 0
At eqm. (1.2-2x) 2x x
As we are given:
Concentration of 
at equilibrium = x = 0.1 M
The expression for equilibrium constant is:
![K_c=\frac{[SO_2]^2[O_2]}{[SO_3]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BSO_2%5D%5E2%5BO_2%5D%7D%7B%5BSO_3%5D%5E2%7D)
Now put all the given values in this expression, we get:
Thus, the value of equilibrium constant (K) is, 0.004
Answer:
Explanation: in exothermic reaction heat is released out
In endothermic reaction heat is absorbed
1) d
2) b because the independent variable is the thing you change/control in an experiment
3) c because the dependent variable is the thing being measured in an experiment
4)hmm it might be d, as c and a are both correct as different sized feeders would make it an unfair test and different types of food would as well
5) c
6) a
7) b obviously because if he activated them at different times then the ones activated last would have an advantage
Answer:
The heat absorbed by water is 39243.75 J.
Explanation:
Given data:
Mass of water = 375.0 g
Heat absorbed by water= ?
Initial temperature = 10.0°C
Final temperature = 35.0 °C
The specific heat capacity of water = 4.186 j/g.°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 35°C - 10°C
ΔT = 25°C
Q = m.c. ΔT
Q = 375.0 g× 4.186 j/g °C × 25°C
Q = 39243.75 J
The heat absorbed by water is 39243.75 J.
Answer:
the carbon monoxide will release blue fumes
