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3 years ago

What is the energy required to go from liquid to gas called answers?

1 answer:

5 0

Answer:
<span>The energy required to go from liquid to gas is called as Latent Heat of Vaporization.

Explanation:
The process of conversion of liquid into gas phase is known as vaporization while the conversion of gas into liquid state is called as condensation. The liquid having stronger intermolecular forces than gases require some energy to break those interactions hence, the heat provided to break these interactions and convert it into gas phase is called as heat of vaporization. Remember, heat of vaporization and heat of condensation are same for a given substance but with different signs.

Example:

Heat of Vaporization of Water = 40.65 kJ/mol

Heat of Condensation of Water = - 40.65 Kj/mol</span>

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The teacher made a 0.5M solution. How is this number read/said?

lukranit [14]

Answer:

It reads as follows: 0.5 moles of solute per liter of solution.

Explanation:

Molarity is the most frequent way of expressing the concentration of solutions in chemistry, and it indicates the number of moles of solute dissolved per liter of solution; is represented by the letter M.

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2 years ago

How is energy level different from orbital?

poizon [28]

Answer:

When an electron is in a particular energy level, it is more likely to be found in some parts of that level than in others. These parts are called orbitals. Orbitals of equivalent energy are grouped in sublevels. Each orbital can contain a maximum of two electrons.

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2 years ago

The mass ratio of H to O in water (H2O) is 1:8. What is the mass

svp [43]

Answer: 1:16

Explanation:

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2 years ago

What is the empirical formula of a compound that contains 49.4% K, 20.3% S, and 30.3% by mass? A) KSO3 B) K2SO3 C) KSO2 D) KSO E

yulyashka [42]

Answer: $K_2SO_3$ .

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of K = 49.4 g

Mass of S = 20.3 g

Mass of O = 30.3 g

Step 1 : convert given masses into moles.

Moles of K= $\frac{\text{ given mass of K}}{\text{ molar mass of K}}= \frac{49.4g}{40g/mole}=1.23moles$

Moles of S= \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{20.3g}{32g/mole}=0.63moles[/tex]

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{30.3g}{16g/mole}=1.89moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For K = $\frac{1.23}{0.63}=2$

For S = $\frac{0.63}{0.63}=1$

For O = $\frac{1.89}{0.63}=3$

The ratio of K: S:O = 2: 1: 3

Hence the empirical formula is $K_2SO_3$ .

7 0

3 years ago

How red blood cells different to animal cells

barxatty [35]

Answer:

By contrast, the red blood cells of mammals lack nuclei and other internal structures found in most animal cells. This simplification allows mammal red blood cells to carry more gas-transporting proteins and to squeeze through smaller blood vessels.

Explanation:

4 0

2 years ago