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Elan Coil [88]
3 years ago
12

Consider these elements: N, Mg, O, F, Al. a. Write the electron configuration for each element. b. Arrange the elements in order

of decreasing atomic radius. c. Arrangetheelementsinorderofincreasingionizationenergy. d. Use the electron configurations in part a to explain the dif- ferences between your answers to parts b and c.
Chemistry
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

N- 1s2 2s2 2p3

Mg- 1s2 2s2 2p6 3s2

O- 1s2 2s2 2p4

F- 1s2 2s2 2p5

Al-1s2 2s2 2p6 3s2 3p1

Explanation:

Order of decreasing atomic radius

Mg,Al, N,O,F

Order of increasing ionization energy

Mg,Al, N,O,F

Reason:

Atomic radius decreases with increase in nonmetallic character. Looking at the electronic configurations, as effective nuclear charge increases, the atom becomes smaller and the attractive force between the nucleus and the outermost electrons increases. Hence, the radius of the atom decreases and ionization energy increases. Note that the addition of more orbital electrons implies addition of more nuclear charge since the both must exactly balance for the atom to remain electrically neutral. The more the electrons in the outermost shell, the higher the first ionization energy.

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What is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at
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Answer:

4,313.43 mmHg is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at  850 mm Hg

Explanation:

Boyle's law says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." This means that if the quantity of gas and the temperature remain constant, the product of the pressure for the volume always has the same value.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

If you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment and you vary the volume of gas to a new value V2, then the pressure will change to P2, it will be true:

P1 * V1 = P2 * V2

In this case:

  • V1=0.335 L
  • P1= ?
  • V2= 1700 mL= 1.7 L (Being 1 L=1000 mL)
  • P2= 850 mmHg

Replacing:

P1*0.335 L=850 mmHg*1.7 L

Solving:

P1=\frac{850 mmHg*1.7 L}{0.335 L}

<u><em>P1=4,313.43 mmHg</em></u>

<u><em>4,313.43 mmHg is the pressure of a sample of gas at a volume of .335 L if it occupies 1700 mL at  850 mm Hg</em></u>

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