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Elan Coil [88]
3 years ago
12

Consider these elements: N, Mg, O, F, Al. a. Write the electron configuration for each element. b. Arrange the elements in order

of decreasing atomic radius. c. Arrangetheelementsinorderofincreasingionizationenergy. d. Use the electron configurations in part a to explain the dif- ferences between your answers to parts b and c.
Chemistry
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

N- 1s2 2s2 2p3

Mg- 1s2 2s2 2p6 3s2

O- 1s2 2s2 2p4

F- 1s2 2s2 2p5

Al-1s2 2s2 2p6 3s2 3p1

Explanation:

Order of decreasing atomic radius

Mg,Al, N,O,F

Order of increasing ionization energy

Mg,Al, N,O,F

Reason:

Atomic radius decreases with increase in nonmetallic character. Looking at the electronic configurations, as effective nuclear charge increases, the atom becomes smaller and the attractive force between the nucleus and the outermost electrons increases. Hence, the radius of the atom decreases and ionization energy increases. Note that the addition of more orbital electrons implies addition of more nuclear charge since the both must exactly balance for the atom to remain electrically neutral. The more the electrons in the outermost shell, the higher the first ionization energy.

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The energy needed to destabilize existing chemical bonds and start a chemical reaction is called ____.
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<span>If all chemical reactions that release free energy tend to occur spontaneously,why haven't all such reactions already occurred? One reason is that most reactions require an input of energy to get started.Before it is possible to form new chemical bonds,even bonds that contain less energy,it is first necessary to break the existing bonds,and that takes energy.The extra energy required to destabilize existing chemical bonds and initiate a chemical reaction is called activation energy.</span>
3 0
3 years ago
A person accidentally swallows a drop of liquid oxygen, O2(l), which has a density of 1.149 g/mL. Assuming the drop has a volume
nasty-shy [4]

Answer:

First, let's determine how many moles of oxygen we have.

Atomic weight oxygen = 15.999

Molar mass O2 = 2*15.999 = 31.998 g/mol

We have 3 drops at 0.050 ml each for a total volume of 3*0.050ml = 0.150 ml

Since the density is 1.149 g/mol,

we have 1.149 g/ml * 0.150 ml = 0.17235 g of O2

Divide the number of grams by the molar mass to get the number of moles 0.17235 g / 31.998 g/mol = 0.005386274 mol

Now we can use the ideal gas law. The equation PV = nRT where P = pressure (1.0 atm) V = volume n = number of moles (0.005386274 mol) R = ideal gas constant (0.082057338 L*atm/(K*mol) ) T = Absolute temperature ( 30 + 273.15 = 303.15 K)

Now take the formula and solve for V, then substitute the known values and solve.

PV = nRT V = nRT/P V = 0.005386274 mol * 0.082057338 L*atm/(K*mol) * 303.15 K / 1.0 atm V = 0.000441983 L*atm/(K*) * 303.15 K / 1.0 atm V = 0.133987239 L*atm / 1.0 atm V = 0.133987239 L

So the volume (rounded to 3 significant figures) will be 134 ml.

8 0
3 years ago
Read 2 more answers
Match the following words.
azamat

Answer:

1. active site

2. substrate.

3. activity

4. cofactor

5. complex

6. coenzyme.

Explanation:

1. A substrate binds to an enzyme at the active site where the reaction occurs.

2. In a catalyzed reaction, a reactant is often called a  substrate.

3  activity is a measure of how fast an enzyme can convert the reagent to the  product.

4. An inorganic substance necessary for the function of some enzymes is called a cofactor.

5. When properly aligned, the enzyme and substrate form an enzyme-substrate (ES) complex.

6. A small organic molecule necessary for the function of some enzymes is  called a  coenzyme.

7 0
3 years ago
slader Consider the following reactions: A. uranium-238 emits an alpha particle; B. plutonium-239 emits an alpha parti- cle; C.
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<u>Answer:</u>

<u>For A:</u> The equation is _{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> The equation is _{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> The equation is _{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

<u>Explanation:</u>

Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

Beta decay process is defined as the process the neutrons get converted into an electron and a proton. The released electron is known as the beta particle. In this process, the atomic number of the daughter nuclei gets increased by a factor of 1 but the mass number remains the same.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

<u>For A:</u> Uranium-238 emits an alpha particle

The nuclear equation for this process follows:

_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> Plutonium-239 emits an alpha particle

The nuclear equation for this process follows:

_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> Thorium-239 emits a beta particle

The nuclear equation for this process follows:

_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

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The wavelength of a given region of the electromagnetic spectrum ranges from 1 x 10-11 - 1 x 10-8 meters. Which waves are found
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The electromagnetic spectrum consists of the full range of known electromagnetic waves. And among them, X-rays has the wavelength of the region 1*10-11 to 1*10-8 meters.
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3 years ago
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