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Elan Coil [88]
3 years ago
12

Consider these elements: N, Mg, O, F, Al. a. Write the electron configuration for each element. b. Arrange the elements in order

of decreasing atomic radius. c. Arrangetheelementsinorderofincreasingionizationenergy. d. Use the electron configurations in part a to explain the dif- ferences between your answers to parts b and c.
Chemistry
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

N- 1s2 2s2 2p3

Mg- 1s2 2s2 2p6 3s2

O- 1s2 2s2 2p4

F- 1s2 2s2 2p5

Al-1s2 2s2 2p6 3s2 3p1

Explanation:

Order of decreasing atomic radius

Mg,Al, N,O,F

Order of increasing ionization energy

Mg,Al, N,O,F

Reason:

Atomic radius decreases with increase in nonmetallic character. Looking at the electronic configurations, as effective nuclear charge increases, the atom becomes smaller and the attractive force between the nucleus and the outermost electrons increases. Hence, the radius of the atom decreases and ionization energy increases. Note that the addition of more orbital electrons implies addition of more nuclear charge since the both must exactly balance for the atom to remain electrically neutral. The more the electrons in the outermost shell, the higher the first ionization energy.

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2 years ago
Give the name and formula of the compound formed from the following elements: (a) sodium and nitrogen; (b) oxygen and strontium;
lisov135 [29]

<u>Answer:</u>

<u>For a:</u> The chemical name and chemical formula formed is sodium nitride and Na_3N

<u>For b:</u> The chemical name and chemical formula formed is strontium oxide and SrO

<u>For c:</u> The chemical name and chemical formula formed is aluminium chloride and AlCl_3

<u>Explanation:</u>

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

  • <u>For a:</u> Sodium and nitrogen:

Sodium is the 11th element of periodic table having electronic configuration of [Ne]3s^1

To form Na^{+} ion, this element will loose 1 electron.

Nitrogen is the 7th element of periodic table having electronic configuration of [He]2s^22p^3.

To form N^{3-} ion, this element will gain 3 electrons.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for sodium nitride is Na_3N

  • <u>For b:</u> Oxygen and strontium

Strontium is the 38th element of periodic table having electronic configuration of [Kr]5s^2.

To form Sr^{2+} ion, this element will loose 2 electrons.

Oxygen is the 8th element of periodic table having electronic configuration of [He]2s^22p^4.

To form O^{2-} ion, this element will gain 2 electrons.  

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for strontium oxide is SrO

  • <u>For c:</u> Aluminium and chlorine

Aluminium is the 13th element of periodic table having electronic configuration of [Ne]3s^23p^1

To form Al^{3+} ion, this element will loose 3 electrons.

Chlorine is the 17th element of the periodic table having electronic configuration of [Ne]3s^23p^5

To form Cl^{-} ion, this element will gain 1 electron.

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for aluminium chloride is AlCl_3

4 0
3 years ago
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