Is y= -1 already solved?

It costs you $10 to draw a sample size n=1 and measure the attribute of interest. you have a budget of $1,200

kicyunya [14]

a. Do you have sufficient funds to estimate the population mean for the attribute of interest with a 95% confidence interval 4 units width? Assume that sd= 12

n= {[(Zalpha/2)^2]*[sd]^2}/ se^2

n= (1.96)^2*(12)^2/ (2)^2

n= 138.297 rounded up to 139

There is not enough funds for this one since you’ll need 139 pieces and it costs 10 a piece, you’ll need 1390.

b. 90% confidence interval

n= {[(Zalpha/2)^2]*[sd]^2}/ se^2

n= (1.645)^2*(12)^2/ (2)^2

n=98

There is enough funds since 98 pieces for 10 a piece is equal to 980.

6 0

4 years ago

7p2 − 7p = 7p ( ______________)

klio [65]

Answer:

7p(p-1)

Step-by-step explanation:

7p²-7p=7p(p-1)

6 0

3 years ago

Read 2 more answers

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$

4 0

3 years ago

Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and th

Vesna [10]

Question is Incomplete; Complete question is given below;

Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and the distance she rides is represented by the variable d. Which statements are true of the scenario? Check all that apply.

a. The independent variable, the input, is the variable d, representing distance.

b. The distance traveled depends on the amount of time Marlene rides her bike.

c. The initial value of the scenario is 16 miles per hour.

d. The equation t = d + 16 represents the scenario.

e. The function f(t) = 16t represents the scenario.

Answer:

OPTION (b) and (e) are the true statements.

Step-by-step explanation:

Given:

$t=>$ time in hours that she rides

$d=>$ distance she rides

We have to find the statements that are true of the scenario.

Solution:

$d=16t$

The equation itself is a linear equation which presents an equation's scenario and time (t) is a independent variable and distance (d) is a dependent variable.

Equation for distance according to function is $f(t)=16t$