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3 years ago

How can slope affect the development of soil what is meant by the term slope orientation?

1 answer:

5 0

According to the United States Department of Agriculture:

<span>"The compass direction that the slope of a land surface faces toward (e.g., north, northwest, south). (After Soil Conserv. Soc. Amer. 1970)"

I hope my answer has come to your help. God bless and have a nice day ahead!</span>

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In 2017, the company SpaceX became the first private company to send supplies to the International Space Station with a reusable

pav-90 [236]

Answer:

Approximately $3.98\; \rm m \cdot s^{-2}$ .

Assumption: air resistance on the rocket is negligible. Take $g = \rm 9.81\; m \cdot s^{-2}$ .

Explanation:

By Newton's Second Law of Motion, the acceleration of the rocket is proportional to the net force on it.

$\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ .

Note that in this case, the uppercase letter $\rm M$ in the units stands for "mega-", which is the same as $10^6$ times the unit that follows. For example, $\rm 1\; Mg = 10^6\; g$ , while $\rm 1\; MN = 10^6\; N$ .

Convert the mass of the rocket and the thrust of its engines to SI standard units:

The standard unit for mass is kilograms: $\displaystyle m = \rm 552\; Mg = 552 \times 10^6\; g \times \frac{1\; \rm kg}{10^3\; g} = 552 \times 10^3 \; kg$ .
The standard for forces (including thrust) is Newtons: $\text{Thrust} = \rm 7.61 \; MN = 7.61 \times 10^6\; N$ .

At launch, the velocity of the rocket would be pretty low. Hence, compared to thrust and weight, the air resistance on the rocket would be pretty negligible. The two main forces that contribute to the net force of the rocket would be:

Thrust (which is supposed to go upwards), and
Weight (downwards due to gravity.)

The thrust on the rocket is already known to be $\rm 7.61 \times 10^6\; N$ . Since the rocket is quite close to the ground, the gravitational acceleration on it should be approximately $9.81\; \rm m \cdot s^{-2} = 9.81 \; N \cdot kg^{-1}$ . Hence, the weight on the rocket would be approximately $9.81\; \rm N \cdot kg^{-1} \times 552 \times 10^3\; kg = 5.41412\times 10^6\; N$ .

The magnitude of the net force on the rocket would be

$\begin{aligned}&\text{Thrust} - \text{Weight} \\ &= 7.61 \times 10^6\; \rm N - 5.41412\times 10^6\; N \\ &\approx 2.19 \times 10^6\; \rm N\end{aligned}$ .

Apply the formula $\displaystyle \text{Acceleration} = \frac{\text{Net Force}}{\text{Mass}}$ to find the net force on the rocket. To make sure that the output (acceleration) is in SI units (meters-per-second,) make sure that the inputs (net force and mass) are also in SI units (Newtons for net force and kilograms for mass.)

$\begin{aligned}\displaystyle &\text{Acceleration} \\ &= \frac{\text{Net Force}}{\text{Mass}} \\ &= \frac{2.19 \times 10^6\; \rm N}{552 \times 10^3\; \rm kg} \\ &\approx \rm 3.98\; \rm m \cdot s^{-2}\end{aligned}$ .

6 0

3 years ago

David is mowing his lawn. He has been riding on the mower at 50m/hr for 2.5 hours? What is the distance of the area David has mo

DaniilM [7]

Answer:

125 metres

Explanation:

Distance = speed × time

Here , speed = 50m/hr

time = 2.5 hr

So,

Distance = 50 × 2.5

=125 m

6 0

3 years ago

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HELP ASAP!! DUE TOMORROW!! FAN & MEDAL!! PLEASE I DON'T UNDERSTAND THIS!! I CAN'T AFFORD TO GET AN F!! ANYTHING WOULD HELP M

USPshnik [31]

If the resulting compound feels hot, then it is exothermic. Otherwise, it is endothermic.

Catalysts and inhibitors both affect the reaction rate of a chemical reaction. A catalyst speeds up the rate of reaction, while an inhibitor does the opposite (slows down the reaction rate).

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3 years ago

What is the mathematical formula for relating velocity, wavelength, and frequency?

Makovka662 [10]

Http://www.emc2-explained.info/Speed-Frequency-and-Wavelength/

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3 years ago

The cycle is a process that returns to its beginning, but it does not repeat

madreJ [45]

False. It does repeat itself

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3 years ago