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Marina86 [1]
3 years ago
11

A mass spectrometer is to be used to separate protons from deuterium nuclei. A deuterium nucleus has the same charge and twice t

he mass as a proton, since it contains an extra neutron. Both the deuterium and the proton nuclei are accelerated by the same voltage. Which of the following statements is true?
Answers:
The deuterium will not be deflected in the mass spectrometer, since it contains a neutron.
Both the proton and the deuterium will move along the same circular path.
The deuterium will have a larger radius of curvature, since it is more massive.
Mass spectrometers cannot be used to analyze nuclei, only molecular ions.
The deuterium will have a smaller radius of curvature, since it is more massive.
Physics
1 answer:
Lina20 [59]3 years ago
3 0

Answer:

The deuterium will have a larger radius of curvature, since it is more massive.

Explanation:

Suppose that the initial velocity of deuterium and protons is the same. According to the relation for centripetal acceleration:

F = \frac{mv^2}{r}

The force is the same due to same electric charge between proton and deuterium. Solving for r:

r = \frac{mv^2}{F}

It means that, the more the mass, the larger the radius due to the directly proportional relation.

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A 95kg clock initially at rest on a horizontal floor requires a 560N horizontal force to set it in motion. After the clock is in
miv72 [106K]

Complete Question

A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.

Answer:

The value for static friction is \mu_s =  0.60

The value for static friction is \mu_k =  0.70

Explanation:

From the question we are told that

The mass of the clock is m  =  95 \  kg

The first horizontal force is F _s  =  560 \  N

    The second horizontal force is    F _k  =  650  \  N

Generally the static frictional force is equal to the first  horizontal force

So

     F _s  =  m  *  g  *  \mu_s

=>   560  =  95  *  9.8  *  \mu_s

=>    \mu_s =  0.60

Generally the kinetic frictional force is equal to the second horizontal force

So

      F _k  =  m  *  g  *  \mu_k

      650 =  95  *  9.8  *  \mu_k

     \mu_k =  0.70

3 0
3 years ago
Only about 50% of the solar energy directed toward Earth penetrates directly to the surface. Explain what happens to the rest of
Tresset [83]

Answer:

it is absorbed or reflected by the atmosphere

Explanation:

In the case when approx 50% only of the solar energy would be directed towards earth and it would be penetrates directly to the surface so the rest or remaining of the radiation would be either absorbed or refected by the atmosphere

So as per the given situation the above represent the answer

hence, the same is to be considered and relevant

4 0
3 years ago
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You ordered a large block of wood with length 5, width 2, and height 1 (each in feet). Unfortunately, the manufacturer can only
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If each side is 0.1 feet extra,
The volume will be 5.1*2.1*1.1= about 11.781.
Perhaps this helps.
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3 years ago
classroom and draw an approxim object Three forces are acting on an object (Figure 1.32) which is in equilibrium. Determine forc
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I’m not good with physics but I’m good with the theory what goes up must come down
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3 years ago
In a physics lab, Asha is given a 10.7 kg uniform rectangular plate with edge lengths 67.3 cm by 53.5 cm . Her lab instructor re
Leya [2.2K]

Answer:

I=2.6363\ kg.m^2

Explanation:

Given:

dimension of uniform plate, (0.673\times 0.535)\ m^2

mass of plate, m=10.7\ kg

Now we find the moment of inertia about the center of mass of the rectangular plate is given as:

I_{cm}=\frac{1}{12} \times m(L^2+B^2)

where:

L= length of the plate

B= breadth of the plate

I_{cm}=\frac{1}{12} \times 10.7\times(0.673^2+0.535^2)

I_{cm}=0.6591\ kg.m^2

We know that the center of mass of the rectangular plane is at its geometric center which is parallel to the desired axis XX' .

Now we find the distance between the center of mass and the corner:

s=\frac{\sqrt{ (0.673^2+0.535^2)}}{2}

s=0.4299\ m

Now using parallel axis theorem:

I=I_{cm}+m.s^2

I=0.6591+10.7\times 0.4299^2

I=2.6363\ kg.m^2

6 0
3 years ago
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