V1: How do you want the answer expressed?
V2:(I. other words..) In what terms do you want the answer expressed?
Ex,
m/s
ft/s
etc,.
Answer:
f=qB/2
m
Explanation:
The cyclotron frequency is the number of revolutions the particle makes in one second. calculate the cyclotron frequency for this particle
solution
The Lorentz force 
is the centripetal force
and makes the particles path to revolve in a circle:
qvB=mv^2/r
radius=r
m=mas of the particle
B=magnetic flux
q=quantity of charge
v=velocity of the particle
v=qBr/m
where v is the velocity of the particle
recall the velocity v=rω
v=2*Pi*f*r
=qBr/m
f=qB/2
m
the cyclotron frequency is therefore f=qB/2
m
the period(the time it take to make a complete oscillation) will be the inverse of frequency
T=2
m/qB
Answer:

Explanation:
Given that
Diameter of small loop d= 2 mm or r=1 mm
Diameter of large loop D= 100 mm or R=50 mm
We know that induce emf given as






So induce current
i=emf/R


Answer:
took longer to complete one oscillation, that means its PERIOD increased, and the distance between the peaks of the graph would be longer.
line would be less. the period of oscillation would have any effect on the graph
Answer:
0.00321 Nm
Explanation:
= Final angular velocity = 3.5 rad/s
= Initial angular velocity = 0
= Angular acceleration
= Angle of rotation = 2 rev
Equation of rotational motion

Moment of inertia is given by

Torque is given by

The torque required is 0.00321 Nm