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Vitek1552 [10]
3 years ago
15

a plumber has a very long piece of pipe is used to run the water parallel to a major place the pipe is cut into two sections 1 s

ection of pipe is 12 feet shorter than the other three fourths of the pipe is 120 feet how long is the longer piece of pipe? can you help me set up an algebraic equation?
Mathematics
1 answer:
tangare [24]3 years ago
4 0
Let x = the shorter piece and Let y = the longer piece. 

(3/4)x = 120 

x = 120 / (3/4) 

x = 120 * (4/3 = 480/3) = 160 feet 

y = 160 + 12
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Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r
slamgirl [31]

Will ran the longest

He ran for 56.57 yards, 13.56 yards longer than James.

Step-by-step explanation:

Step 1 :

Will ran the diagonal across a square field measuring 40 yards in each side.

The diagonal of a square can be obtained by the square root of the sum of the squares of its 2 sides [Because it forms the hypotenuse of a right angle triangle]

Hence when the side is 40 yards , the diagonal would be

\sqrt{40^{2} + 40^{2}}  = \sqrt{1600 + 1600}   = \sqrt{3200}  =56.57 yards

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Step 2 :

James ran the diagonal of a rectangular field with 25 yards length and 35 yards width.

The diagonal of the rectangle can be obtained by the square root of the sum of squares of its length and width.

Hence when the length is 25 yards and width is 35 , the diagonal would be

\sqrt{35^{2} + 25^{2}}  = \sqrt{1225 + 625}} = \sqrt{1850} = 43.01 yards

So James ran for 43.01 yards

Step 3 :

Will ran for 56.57 yards and 43.01 yards.

Hence Will ran for longer distance of 56.57 yards, which is 13.56 yards more than James.

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Step-by-step explanation:

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