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photoshop1234 [79]

3 years ago

8

You will have BRAINLYESTWhich net represents this solid figure?

1 answer:

Gre4nikov [31]3 years ago

4 0

Answer:

D

Step-by-step explanation:

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Robert, a ninth-grader, has just been told, "The reason you’re having so much trouble with division is that you have never maste

Brums [2.3K]

Answer:

Diagnostic

Step-by-step explanation:

The teacher made a diagnostic decision relative to Roberts skill level. Before she made this decision, she first started with the process of evaluation to know his strength and also establish his weakness. With the knowledge she has gotten she now plans to him with meaningful learning and an efficient curriculum that would help him in mastering multiplication first before division.

7 0

3 years ago

Please help. the semester isd almost over need this

Zolol [24]

The answer is a because it is the only one that decreases without ever increasing

8 0

3 years ago

Solve for a.<br> -1/4a - 4 = 7/4a -3<br> A=

irakobra [83]

Answer:

a = -1/2

Step-by-step explanation:

- 1/4a - 4 = 7/4a - 3

- 1/4a - 7/4a = - 3 + 4

- 8/4a = 1

- a = 1 / 8/4

- a = 1 * 4/8

- a = 4/8

- a = 1/2

a = - 1/2

3 0

3 years ago

2.4 *10^2<br> 5.25*10^2<br> 2.53*10^1<br> 1.8*10^3<br> Order from least to greatest

OLEGan [10]

2.4*10^2 (2)
2.53*10* (1)
5.25*10^1 (3)
1.8*10^3 (4)

7 0

3 years ago

A survey recently reported that the mean national annual expenditure for inpatient and outpatient services of all persons over 6

zlopas [31]

Using the z-distribution, it is found that the p-value for this test is of 0.0375.

At the null hypothesis, it is <u>tested if the expenses are the same as the national average</u>, that is, of $5,423. Hence:

$H_0: \mu = 5423$

At the alternative hypothesis, it is <u>tested if it is higher</u>, hence:

$H_1: \mu > 5423$

We have the <u>standard deviation for the population</u>, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the <u>parameters</u> are: $\overline{x} = 5516, \mu = 5423, \sigma = 979, n = 352$

The value of the <u>test statistic</u> is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{5516 - 5423}{\frac{979}{\sqrt{352}}}$

$z = 1.78$

The p-value is the probability of finding a sample mean above $5,516, which is <u>1 subtracted by the p-value of z = 1.78</u>.

Looking at the z-table, z = 1.78 has a p-value of 0.9625.

1 - 0.9625 = 0.0375

Hence, the p-value for this test is of 0.0375.

A similar problem is given at brainly.com/question/25549474

7 0

3 years ago