A particle is moving in a circular path of radius r . The displacement after half a circle would be
1 answer:
Answer:
2r
Explanation:
As we know that
The displacement is the total distance measured between the initial or start and final or destination point
If particle cover half path of the circle, the displacement can easily find out by considering the distance between the start and destination point
We attached the diagram for better understanding
As per the diagram.
The displacement after half-circle is
AB = OA + OB
= r + r
= 2r
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Answer:
1)
2)
Explanation:
Given data:
speed of sound v = 1540 m/s
frequency f = 1.40 MHz = 1.40 \times 10^6 Hz
density
1) we know that
2) we know that
Refer to the diagram shown below.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.
Still-water speed = 9.5 m/s
River speed = 3.75 m/s down stream.
The velocity of the swimmer relative to the bank is the vector sum of his still-water speed and the speed of the river.
The velocity relative to the bank is
V = √(9.5² + 3.75²) = 10.21 m/s
The downstream angle is
θ = tan⁻¹ 3.75/9.5 = 21.5°
Answer: 10.2 m/s at 21.5° downstream.