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MrRa [10]
3 years ago
10

What is happening to the light in the illustration?

Physics
2 answers:
sergeinik [125]3 years ago
7 0

Here, we are seeing light pass through a very dense medium. That medium is the air, then it moves to become the water. When this aforementioned light passes from the less dense area, to the more dense area, the light is usually refracted. Refraction is otherwise known as being bent, as well. Therefore, it's your last selection.

That's why when you look at the image, the light doesn't seem straight anymore. It's slightly tilted, being bent a tad. Though, it's still travelling downwards. However, the light won't travel to far down in the water.

D) It is being refracted.

For future reference, here's my dense properties here.

Water: Higher Density

Air: Lower Density

That's essentially why the refraction is occurring here. Also, if you aren't familiar with what a medium is, I suggest you overlook it. It can be rather useful. A medium is a substance that carries a wave through it. Some waves may require a medium to even operate/occur.

For instance, mechanical waves require a medium.

rjkz [21]3 years ago
5 0

D). It is being Refracted

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Answer:

11.4333 m.s^{-2}

Explanation:

Given:

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∵The apparent weight increases it means that the spacecraft is accelerating in the direction opposite to the gravity and having the value greater than 9.8m.s^{-2}

DIfference in the weight,

F= M.g - m.g

F= (79.3787 -68.0389 )\times 9.8

F=11.3398\times 9.8\\F=111.13004 N

This difference in weight is due to the difference in acceleration of the gravity and the spacecraft.

So, the quantity of acceleration responsible for this difference in weight:

F=m.\Delta a.................(1)

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m= mass of the body being accelerated

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from eq. (1)

111.13004 = 68.0389 \times \Delta a

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∴The actual accelerationof the spacecraft:

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3 years ago
What happens when the object is placed at F? Explain<br> your answer.
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Answer:

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Answer:

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Area of cross section = A = π r² = π (0.027/2)² = 0.00057255 m²

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