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MrRa [10]
3 years ago
10

What is happening to the light in the illustration?

Physics
2 answers:
sergeinik [125]3 years ago
7 0

Here, we are seeing light pass through a very dense medium. That medium is the air, then it moves to become the water. When this aforementioned light passes from the less dense area, to the more dense area, the light is usually refracted. Refraction is otherwise known as being bent, as well. Therefore, it's your last selection.

That's why when you look at the image, the light doesn't seem straight anymore. It's slightly tilted, being bent a tad. Though, it's still travelling downwards. However, the light won't travel to far down in the water.

D) It is being refracted.

For future reference, here's my dense properties here.

Water: Higher Density

Air: Lower Density

That's essentially why the refraction is occurring here. Also, if you aren't familiar with what a medium is, I suggest you overlook it. It can be rather useful. A medium is a substance that carries a wave through it. Some waves may require a medium to even operate/occur.

For instance, mechanical waves require a medium.

rjkz [21]3 years ago
5 0

D). It is being Refracted

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true

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If the mass of the ladder is 12.0 kgkg, the mass of the painter is 55.0 kgkg, and the ladder begins to slip at its base when her
Marysya12 [62]

Answer:

 μ = 0.336

Explanation:

We will work on this exercise with the expressions of transactional and rotational equilibrium.

Let's start with rotational balance, for this we set a reference system at the top of the ladder, where it touches the wall and we will assign as positive the anti-clockwise direction of rotation

          fr L sin θ - W L / 2 cos θ - W_painter 0.3 L cos θ  = 0

          fr sin θ  - cos θ  (W / 2 + 0,3 W_painter) = 0

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Now let's write the equilibrium translation equation

     

X axis

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the friction force has the expression

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Y Axis

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we substitute

      fr = μ (W + W_painter)

we substitute in the endowment equilibrium equation

     μ (W + W_painter) = cotan θ  (W / 2 + 0,3 W_painter)

      μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)

we substitute the values ​​they give

      μ = cotan θ  (12/2 + 0.3 55) / (12 + 55)

      μ = cotan θ  (22.5 / 67)

      μ = cotan tea (0.336)

To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45

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5 0
4 years ago
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o-na [289]

Answer:

w=255

Explanation:

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ΔE = Q - w

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To bring the system back to its initial state after this, the internal energy must change by +149J (the system myst gain back the 149 J of energy it lost).  We are told that the system loses 106 J of heat in returning to its initial state, so the work involved is given by:

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Explanation
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