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valina [46]
3 years ago
11

Positive charge is distributed uniformly throughout a non-conducting sphere. The highest electric potential occurs: A. Far from

the sphere B. Just outside the surface C. At the surface D. Halfway between the center and surface E. At the center
Physics
1 answer:
Ilya [14]3 years ago
6 0

Answer:E

Explanation:

At the center

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If we drop two iron balls, one ball is bigger than another one, from
loris [4]

Answer:

The bigger one. Ignoring air resistance, they will fall at the same speed, but the bigger one will hit first because it sticks out lower.

Explanation:

7 0
3 years ago
2. What is the magnitude of the force a 1.5 C charge exerts on a 3.2 C charge
lesya [120]

The magnitude of the force is F=1.68×10 ^20  N

<u>Explanation:</u>

<u>Given data</u>

q1 =1.5  10 ^6 q2=3.2 10^6   r=1.5

<u>We have the formula</u>

By the coulomb's law

F= K. q1 ×q2 / r²

The K value is given by    

8.99  10^9 Nm²/ c²

substitute the values we get,

F= ( 8.99×  10^9 Nm²/ c²) ×(<u>1.5 ×10 ^6</u>)×(<u>3.2 ×10 ^6</u>)/ (1.6 m² )

F=1.68×10 ^20  N

The magnitude of the force is F=1.68×10 ^20  N

4 0
3 years ago
Find the total power developed in the circuit. Express your answer using three significant figures and include the appropriate u
BabaBlast [244]

Answer:

37 W

Explanation:

Power is the time rate of dissipation or absorbing energy. The power supplied or absorbed by an element is the product of the current flowing through the element and the voltage across the element. Power is measured in watts. If the power is positive then it is absorbed by the element and if it is negative then it is supplied by the element.

Power = voltage * current

For element A: Power = 36 V * -4 A = -144 W

For element B: Power = -20 V * -4 A = 80 W

For element C: Power = -24 V * 4 A = -94 W

For element D: Power = -80 V * -1.5 A = 120 W

For element E: Power = 30 V * 2.5 A = 75 W

The total power developed in the circuit = sum of power through the element = (-144 W) + 80 W + (-94 W) + 120 W + 75 W = 37 W

6 0
3 years ago
How much work can a 22kw car engine do in 60 seconds
Sindrei [870]

Answer:

13.2 x 10^5 J

Explanation:

Power = work/time

Given

Power = 22kw

= 22 x 1000 = 22000w

Time = 60 secs

Therefore

22000 = work/60

Cross multiply

Work = 22000 x 60

= 1320000

= 13.2 x 10^5J

6 0
3 years ago
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Which conditions are usually the effect of a low air pressure system? clear, dry weather cloudy, wet weather cold, dry weather h
qaws [65]
Your answer is hot dry waether
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