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Cerrena [4.2K]
4 years ago
8

Please please help me!!

Mathematics
1 answer:
love history [14]4 years ago
6 0

Answer:

The submarine is  307.8 yards below sea level.

Step-by-step explanation:

Since the 500 yards are the hypotenuse of the right angle triangle, the acute angle opposite the side of the triangle we need to find is known (38^o), we can use the sine function to solve the problem:

sin(\theta)=\frac{opposite}{hypotenuse} \\sin(38^o)=\frac{x}{500} \\500\,*\,sin(38^o)=x\\x = 307.8307\,\,yards

which rounded to the nearest tenth is : 307.8 yards

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Answer:

-2

Step-by-step explanation:

Start on -5 on the left side of the number line, jump from -5 three times to the right of the number line since ( - - ) means to add. As you jump draw "bridges" and by the time you have completed the amount of jumps you have to do you'll end up with a difference of -2.

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3 years ago
Now given a rope hanging from the top of a pole. The end lying on the ground is 3 chi long. When tightly stretchedit is 8 chi fr
drek231 [11]

Answer:

Height of the pole = 9.17 chi.

Length of the rope = 12.17 chi.

Step-by-step explanation:

Given that the rope is hanging from the top of a pole having height x chi and the portion of the rope lying on the ground is 3 chi.

So, the length of the rope= x + 3 chi.

Let AB represents the pole in the figure, and one end of the rope is at point A.

When the rope is tightly stretched, let C be the other end of the rope as shown in the triangle.

The length of the rope = AC.

\Rightarrow AC=x+3 chi.

Distance from the bottom of the pole, point A, to the other end of the pole, point B, is 8 chi.

So, BC=8 chi.

As the triangle ABC is a right-angled triangle, so by using Pythagoras theorem,

AC^2= AB^2+BC^2

\Rightarrow (x+3)^2=x^2+8^2

\Rightarrow x^2+6x+9=x^2+64

\Rightarrow 6x=64-9=55

\Rightarrow x=55/6=9.17 chi.

Hence, the height of the pole, AB=x=9.17 chi,

and the length of the rope, x+3=9.17+3=12.17 chi.

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