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4 years ago

@Tarunax3 Help please!

Mathematics

1 answer:

insens350 [35]4 years ago

6 0

In order to answer this, you need to find the equation of the line. The equation of a line is y= mx + b; mx being the slope and b being the y- intercept. The y intercept is located at (0, 20).
To find the slope, take two points. Let's use (1,40) and (2,60).
Use the slope formula: (y1 - y2)/(x1 - x2)
(60-40)/(2-1)= 20/1= 20.
The slope is 20, the equation is: y = 20x + 20.
Now plug 10 into x:
y = 20(10) + 20
y = 220
Your answer is 220.

You might be interested in

in the number 85,549 the 5 in the hundreds place is. times that of the 5 in the thousands place.

Oksanka [162]

The value of 5 in the hundreds place is 500

The value of 5 in the thousands place is 5000

To find 500 is how many times in 5000 we will divide them

$\frac{500}{5000}=\frac{1}{10}$

Then 500 is 1/10 times that 5000

8 0

1 year ago

9) 337<br>The 3 in the hundreds place is _<br>the value of the 3 in the tens place.

Aliun [14]

Answer:

ten times the value of the 3 in the tens place.

Step-by-step explanation:

I believe that is what your teacher is looking for. 30 times 10 equals 300.

hope this helps !

if this did please consider marking brainliest i would appreciate it

6 0

3 years ago

F(x)=(x-6)e^-3x find the interval in which f(x) is increasing, the intervals on which f(x) is decreasing, and the local extrema

Over [174]

$\bf f(x)=(x-6)e^{-3x}\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=1\cdot e^{-3x}+(x-6)-3e^{-3x}\implies \cfrac{dy}{dx}=e^{-3x}[1-3(x-6)]
\\\\\\
\cfrac{dy}{dx}=e^{-3x}(19-3x)\implies \cfrac{dy}{dx}=\cfrac{19-3x}{e^{3x}}$

set the derivative to 0, solve for "x" to get any critical points
keep in mind, setting the denominator to 0, also gives us critical points, however, in this case, the denominator will never be 0, so... no critical points from there

there's only 1 critical point anyway, and do a first-derivative test on it, check a number before it and after it, to see what sign the derivative has, and thus, whether the graph is going up or down, to check for any extrema

5 0

3 years ago

Use the standard algorithm to find the product of 853 and 59. Record the product of multiplying by the ones digit, the product o

bearhunter [10]

The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327

<h3>How to determine the product of the numbers?</h3>

The numbers are given as

853 and 59

By using the standard algorithm i.e. the partial product method, we have the following equation

853 * 59 = 853 * (50 + 9)

Open the bracket

So, we have

853 * 59 = 853 * 50 + 853 * 9

Evaluate the products

So, we have

853 * 59 = 42650 + 7677

The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650

Next, we evaluate the sum

853 * 59 = 50327

This means that the final product is 50327