<span>1) Find the equation of the
line that passes through (x1, y1) and (x3, y3).
We have it: </span>y = 0.4x + 38<span>2) Find the equation of the
line parallel to the previous line that passes through (x2, y2).
</span><span>That is: y = 0.4x + 59
</span><span>3) Find the weighted
average of the
y-intercepts. b=(b1+b2+b1)/3 = (38+59+38)/3
b= 45
The median-median line is the line parallel to the previous two lines with the weighted y-intercept.Hence, Y = 0.4 x + 45 is the answer</span>
Answer: (0,-2)
hope that answered your question
D=4Step-by-step explanation:
Answer:
33+12t−21t^2
Step-by-step explanation:
(2t-7)²-(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².
4t^2−28t+49−(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².
4t^2−28t+49−(25t^2−40t+16)
To find the opposite of 25t^2
−40t+16, find the opposite of each term.
4t^2−28t+49−25t^2−40t+16
Combine 4t^2 and −25t^2 to get −21t^2.
−21t^2−28t+49+40t−16
Combine −28t and 40t to get 12t.
−21t^2+12t+49−16
Subtract 16 from 49 to get 33.
−21t^2+12t+33
Swap terms to the left side.
33+12t−21t^2
I hope this helped!
