Answer:
The cross section would be a square.
Step-by-step explanation:
The 2 ends of the rectangular prism are squares while the other 4 sides are rectangles. A cross section would be perpendicular to the rectangles, making the cross section a square. The cross section would be parallel to the end squares.
Answer:
C. Because (-3)^2 is NOT equal to -9
Step-by-step explanation:
Answer:
cos(O) = 39 / 89
Step-by-step explanation:
Given:
ΔOPQ, where
∠Q=90°
PO = 89
OQ = 39
QP = 80
cosine of ∠O?
cos(O) = Adjacent / Hypotenuse
cos(O) = 39 / 89
1st Bagel; $0.79. 2nd Bagel; $0.67. 3rd Bagel; $0.70. 4th Bagel; $0.75. So B would be the correct answer, given 67¢ is cheaper ;)))))))
Answer:

Step-by-step explanation:
Given the integral equation

According to integration by part;

u = x, dv = e^7x
du/dx = 1
du = dx

Substitute the given values into the formula;
