Newtons third law of motion is:
for every action, there is an opposite and equal reaction
Hope this helps!
Answer:
if your going 15000 mph all you can do is accelerate or go fast unless there is a opposite
Explanation:
Answer:
F= 56,1 N :
Explanation:
We apply Newton's first law for balancing forces system.
We take the x axis in the direction of the ramp with a 16.1° slope.
∑Fx= 0
∑Fx: algebraic sum of forces ( + to the right, - to the left)
Problem development:
Look at the free body diagram :
The only forces that act on the box are the weight and tension of the rope because there is no friction.
T: Rope tension (N)
W :Box weight (N)
∑Fx= 0
Tx-Wx=0
Tx =Tcos( 43.2°- 16.1°)= Tcos ( 27.1°)
Wx= W*sen 16.1°= m*g*sen 16.1°=18.4*9.8* sen 16.1° = 50N
Tcos ( 27.1°)-50=0
Tcos ( 27.1°) = 50
T = (50) / (cos ( 27.1°))
T = 56,1 N
T=F= 56,1 N
Answer:
5.35 rad/s
Explanation:
From the question, we are toldthat an Identical particles are placed at the 50-cm and 80-cm marks on a meter stick of negligible mass. This rigid body is then mounted so as to rotate freely about a pivot at the 0-cm mark on the meter stick.
Solving this question, the potential energy of the particles must equal to the Kinectic energy i.e
P.E=K.E
Mgh= m½Iω²-------------eqn(*)
Where M= mass of the particles
g= acceleration due to gravity= 9.81m/s^2
ω= angular speed =?
h= height of the particles in the stick on the metre stick= ( 50cm + 80cm)= (0.5m + 0.8m)= 130cm=1.3m
If we substitute the values into eqn(*) we have
m×9.81× (1.3m)= 1/2× m×[ (0.5m)² + [(0.8m)²]× ω²
m(12.74m²/s²)= 1/2× m× (0.25+0.64)× ω
m(12.74m²/s²)= 1/2× m× 0.89× ω²
We can cancel out "m"
12.74= 1/2×0.89 × ω²
12.74×2= 0.89ω²
25.48= 0.89ω²
ω²= 28.629
ω= √28.629
ω=5.35 rad/s
Hence, the angular speed of the meter stick as it swings through its lowest position is 5.35 rad/s
Answer:
1) 1.67eV
2) 505nm
Explanation:
The maximum kinetic energy of photoelectrons ,
KEmax=λhc−W=(0.3×10−6)(1.6×10−19)(6.62×10−34)(3×108)eV−2.46eV=1.67eV
If λ0 is the cut-off wavelength, W=λ0hc
or λ0=Whc=2.46×1.6×10−19(6.62×10−34)(3×108)=5.05×10−7m=505×10−9=505nm
<em>We know that the work function is the minimum photon energy for taking place of photoelectric effect. </em>
