Four consecutive integers... n, n+1, n+2, n+3.
The product of the 1st and 4th is four less than twice the 1st multiplied by the 4th.
n(n+3)=2n(n+3)-4 perform indicated multiplications...
n^2+3n=2n^2+6n-4 subtract n^2 from both sides
3n=n^2+6n-4 subtract 3n from both sides
n^2+3n-4=0 factor
n^2-n+4n-4=0
n(n-1)+4(n-1)=0
(n+4)(n-1)=0, and since n>0
n=1
So the four numbers are 1, 2, 3, 4
check...
1(4)=2(1)4-4
4=8-4
4=4
Answer:
the answer d , the second answer is b, the third answer is b,
Step-by-step explanation:
Answer:
(1,4) and (1,0)
Step-by-step explanation:
These have the same first coordinate and different second coordinates, meaning that it cannot be a function. For it to be a function, the x coordinates have to be different numbers.
One simple question.... I see no zeros :
