Answer:
We know that ,
So ,
we can add 2 pi to it since there will be no change in the value
Also,
Answer : Option B
Answer:
The correct option is B.
Step-by-step explanation:
Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .
Draw a diagonal AC.
In triangle BCA and DAC,
AC\cong ACAC≅AC (Reflexive Property of Equality)
\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)
\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)
The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.
By ASA postulate,
\triangle BCA\cong \triangle DAC△BCA≅△DAC
Therefore option B is correct
1st:x
2nd x+2
3rd: x+4
(x)+(x+2) = 3(x+4)-31
distribute
2x+2 = 3x+12-31
2x+2 =3x-19
subtract 2x from each side
2 = x-19
add 19 to each side
21 =x
Answer: 21,23,25
The dimensions would be 40 m by 40 m.
To maximize area and minimize perimeter we make the dimensions as close to equal as possible. Since we only need fencing on 3 sides, 120/3 = 40; we can use 40 for each side.
Answer:
Step-by-step explanation:
Subtract 295 from both sides:
Add 33x to both sides:
Divide both sides by 72:
