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aalyn [17]
3 years ago
12

Sid needs to put 88 ounces of com in 6 containers. Write 88/6 as a mixed numeral.​

Mathematics
1 answer:
Ann [662]3 years ago
7 0

Answer:

the answer is  14 2/3, hope this answers your question

Step-by-step explanation:

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I need help guys ok thinks
Serhud [2]
3/9 + 1/2 = 5/6
2 1/3 + 2 1/4 = 4 and 7/12
7 0
3 years ago
A submarine sits at –300 meters in relation to sea level. Then it descends 115 meters. What is its new position in relation to s
Dovator [93]

Answer:

-415 feet

Step-by-step explanation:

-300-115 = -415

7 0
3 years ago
The check-cashing store also makes one-month add-on interest loans at 7.8 percent discount interest per week. Thus if you borrow
masya89 [10]

Answer:

APR = 416%

EAR = 5370.60%

Step-by-step explanation:

Given:

Interest rate = 7.8% per week

Now,

In an year there are total 52 weeks

thus,

The APR (Annual percentage rate) = Interest rate × Total weeks in an year

or

APR = 8% × 52

or

APR = 416%

and, EAR ( Effective Annual Rate ) = ( 1 + r )ⁿ - 1

Here,

r is the interest rate per week

n is the total weeks in an year

thus,

EAR ( Effective Annual Rate ) = ( 1 + 8% )⁵² - 1

= ( 1 + 0.08 )⁵² - 1

= 53.7060

or

53.7060 × 100% = 5370.60%

5 0
3 years ago
62\100 <br> simplest form<br><br> 45\100<br> simplest form
vlabodo [156]

Answer:

62/100= 31/50

45/100= 9/20

Step-by-step explanation:

Divide 62 and 100 by two to simplify

Divide 45 and 100 by 5 to simplify

5 0
3 years ago
Read 2 more answers
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}&#10;\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}&#10;\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}&#10;\\&#10;\\ \text{z-score} = \frac{720 - 600}{100}&#10;\\&#10;\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) &#10;\\ = P(z \ \textgreater \  1.2)&#10;\\ = 1 - P(z \leq 1.2)&#10;\\ = 1 - 0.885&#10;\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
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