The equation of the perpendicular line is y + 7 = -1/7(x - 3)
<h3>How to determine the line equation?</h3>
The equation is given as
y = 7x + 14
Also, from the question
The point is given as
Point = (3, -7)
The equation of a line can be represented as
y = mx + c
Where
Slope = m
By comparing the equations, we have the following
m = 7
This means that the slope of y = 7x + 14 is 7
So, we have
m = 7
The slopes of perpendicular lines are opposite reciprocals
This means that the slope of the other line is -1/7
The equation of the perpendicular lines is then calculated as
y = m(x - x₁) +y₁
Where
m = -1/7
(x₁, y₁) = (3, -7)
So, we have
y = -1/7(x - 3) - 7
Evaluate
y = -1/7(x - 3) - 7
Add 7 to both sides
y + 7 = -1/7(x - 3)
Hence, the perpendicular line has an equation of y + 7 = -1/7(x - 3)
Read more about linear equations at
brainly.com/question/4074386
#SPJ1
Answer:
4/8 = 20/x
20 x 8 = 160
160 ÷ 4 = 40
the student will attend 40 weeks of school
Answer:
Degree is 2 so it is a quadratic.
The number of terms is 2 so it is a binomial.
It is a binomial quadratic.
Step-by-step explanation:
Let's find the degree of the polynomial first. I'm going to consider first the degrees of 5x^2 and 3.
The degree of the monomial 5x^2 is 2 because x is the only variable and it's exponent is 2.
The degree of the monomial 3 is 0 because there is no variable.
The degree of 5x^2+3 is therefore 2 because that is the highest degree of the monomials contained with in this polynomial 5x^2+3.
Degree 2 has a special name.
The special name for a degree 2 polynomial is quadratic.
Let's look at the number of terms in 5x^2+3.
Terms are separated by addition and subtraction symbols so there are two terms.
There is a special name for a two-termed polynomial, it is binomial.
So this is the following information I collected on our given polynomial:
Degree is 2 so it is a quadratic.
The number of terms is 2 so it is a binomial.
It is a binomial quadratic.
