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devlian [24]
3 years ago
15

Solve the system of equations y=2x+4 y=x^2+x-2

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

Answer:

The two intersections would be (3, 10) and (-2, 0)

Step-by-step explanation:

To solve this system of equations, set the two equations equal to each other and solve for x.

2x + 4 = x^2 + x - 2

2x = x^2 + x - 6

0 = x^2 - x - 6

0 = (x - 3)(x + 2)

Now set the parenthesis equal to zero to get the x values.

x - 3 = 0

x = 3

x + 2 = 0

x = -2

Now we know the x values of each interception. We can find the y values by plugging into either equation.

y = 2x + 4

y = 2(3) + 4

y = 6 + 4

y = 10

y = 2x + 4

y = 2(-2) + 4

y = -4 + 4

y = 0

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the zeros of a parabola are -4 and 2, and (6, 10) is a point on the graph. which equation can be solved to determine the value o
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Sure this question comes with a set of answer choices.

Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.

Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant.  This is, the equation has the form:

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