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2 years ago

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Find the equation whose graph is a parabola with vertex (2,4), vertical axis of symmetry, and contains the point (1,1). Express

your answer in the form ax^2+bx+c
Please don't answer this unless you actually have the correct answer.

1 answer:

gtnhenbr [62]2 years ago

4 0

Answer:

a

Step-by-step explanation:

You might be interested in

Rewrite the function by completing the square.

ddd [48]

Answer:

f(x) = (x -6)² +14

Step-by-step explanation:

Completing the square involves writing part of the function as a perfect square trinomial.

<h3>Perfect square trinomial</h3>

The square of a binomial results in a perfect square trinomial:

(x -h)² = x² -2hx +h²

The constant term (h²) in this trinomial is the square of half the coefficient of the linear term: h² = ((-2h)/2)².

<h3>Completing the square</h3>

One way to "complete the square" is to add and subtract the constant necessary to make a perfect square trinomial from the variable terms.

Here, we recognize the coefficient of the linear term is -12, so the necessary constant is (-12/2)² = 36. Adding and subtracting this, we have ...

f(x) = x² -12x +36 +50 -36

Rearranging into the desired form, this is ...

f(x) = (x -6)² +14

__

<em>Additional comment</em>

Another way to achieve the same effect is to split the given constant into two parts, one of which is the constant necessary to complete the square.

f(x) = x² -12x +(36 +14)

f(x) = (x² -12x +36) +14

f(x) = (x -6)² +14

6 0

1 year ago

What is the equation of the graph below?

Molodets [167]

Answer:A

Step-by-step explanation:

look at the graph and u will find the same answer

6 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B50x%7D%20%20-%20%20%5Csqrt%7B18x%7D" id="TexFormula1" title="\sqrt{50x} - \sqrt{18

jeka57 [31]

Answer:

Step-by-step explanation:

8 0

2 years ago

Solve for c:<br><br><br><br> c + (-20) = -12

alexira [117]

Answer:

8

Step-by-step explanation:

Isolate and solve for C

$c + (-20) = -12\\c - 20 = -12\\c = -12+20\\c = 8$

6 0

2 years ago

Read 2 more answers

F ind the volume under the paraboloid z=9(x2+y2) above the triangle on xy-plane enclosed by the lines x=0, y=2, y=x

olga nikolaevna [1]

Answer:

The answer is 48 units³

Step-by-step explanation:

If we simply draw out the region on the x-y plane enclosed between these lines we realize that,if we evaluate the integral the limits all in all cannot be constants since one side of the triangular region is slanted whose equation is given by y=x. So the one of the limit of one of the integrals in the double integral we need to evaluate must be a variable. We choose x part of the integral to have a variable limit, we could well have chosen y's limits as non constant, but it wouldn't make any difference. So the double integral we need to evaluate is given by,

$V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {z} \, dx dy\\V=\int\limits^2_0 {} \, \int\limits^{x=y}_0 {9(x^{2}+y^{2})} \, dx dy$

Please note that the order of integration is very important here.We cannot evaluate an integral with variable limit last, we have to evaluate it first.after performing the elementary x integral we get,

$V=9\int\limits^2_0 {4y^{3}/3} \, dy$

After performing the elementary y integral we obtain the desired volume as below,

$V= 48 units^{3}$

4 0

2 years ago