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Masja [62]
3 years ago
9

What is the equation of Pythagorean Theorem?

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer: a²= b²+c²

Step-by-step explanation:

Pythagorean theorem states the sum of the square of the other sides of Right angled triangle equals to the square of the longest side (hypotenus) of such triangle

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Find the product of 2r^2(6r^3+14r^2-30r+14)
mylen [45]

Answer:

<em>12 </em>r^{5}<em> + 28 </em>r^{4}<em> - 60 r³ + 28 r² </em>

Step-by-step explanation:

a(b ± c) = ab ± ac (distributive property)

a^{m} * a^{n} = a^{m+n}

2r²(6r³ + 14r² - 30r + 14) = <em>12 </em>r^{5}<em> + 28 </em>r^{4}<em> - 60 r³ + 28 r²</em>

6 0
3 years ago
Read 2 more answers
I need to know the answer
MissTica

If Sachiko lets x represent the length of the side of the square and she wants to find the length of the perimeter of the square, it is appropriate for her to ...

... B. Set the area equal to x², solve for x, and then multiply the value of x by 4.

_____

The area of a square of side length x is x·x = x². The perimeter of a square of side length x is x+x+x+x = 4·x.

3 0
3 years ago
You run and miles on Friday the same amount on Saturday and 40 miles and Sunday right in expression in simplest form that repres
bearhunter [10]

Answer:

Step-by-step explanation:

Friday = x miles

Saturday = x miles

Sunday = 40 miles

Cummulative = 2x + 40

4 0
4 years ago
Find the infinite geometric sum of 80 + 10 +1.25 + ... to 5 decimal places past the decimal point.
SIZIF [17.4K]

first term.

a= 80

second term. a2=10

so Common ratio r=a2/a =10/80=1/8=0.125

checking for the validity of common ratio.

a2×r=10×1/8=10×0.125=1.25 =a3= Third term.

Hence it is true.

Now 4th Term =1.25/8=0.15625

It can be observed that 4TH term Has digit that is 5 places past the decimal point.

Hence, 0.15625 is the terminating number as per the question.

So the required sum is.

S=a+a2+a3+a4

->S=80+10+1.25+0.15625

->S= 91.40625

Hope it helps...

Regards,

Leukonov/Olegion.

7 0
4 years ago
Seperate the number 53 into 3 parts so that the second number is 3 less than the first number and the third number is twice the
irga5000 [103]
Hello,

Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2*a=2*15.9=31.8
b=a/3=15.9/3=5.3

Proof: a+b+c=15.9+5.3+31.8=53

The second number is 5.3
7 0
3 years ago
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