Answer:
The correct answer is - 1/41,493
Explanation:
Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:
2pq + 2pqF. ( where F is the inbreeding coefficient).
The frequency of the two different hoozygotes in inbred population can be calculated as:
p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.
Given: Frequency of Alkaptonuria (q 2) = 1:500, 000
=> q = 1/707
p = 706/707 ( Approx values)
solution:
Inbreeding coefficient (F) = 1/64
Therefore,
Frequency of Alkaptonuria in second cousins= q 2 + pqF
= 1/500, 000 + (706/707 x 1/707) x (1/64)
= 1/500, 000 + 1/45, 248
= 1/41,493 (approx)
Answer:
If a protein or molecule is taken up by the cell and must be digested it will make use of <u>lysosomes</u>.
Explanation:
Lysosomes are membrane-bound organelles that have a wide range of functions but their main 'job' is to break down large molecules into smaller molecules or to digest molecules that are present in excessive or unnecessary amounts. This is why <u>they contain important digestive enzymes known as hydrolitic enzymes.</u>
Lysosomes can break down, for example, large proteins into amino acids to provide the cell with the necessary nutrients.
Answer:
good luck on that one... ........... ..
