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kondor19780726 [428]
3 years ago
14

How to solve pythagorean theorem when a is missing a=x b=17 c=15

Mathematics
2 answers:
raketka [301]3 years ago
4 0

Answer:

the Pythagorean theorem is

a ^{2}  + b {}^{2}  = c {}^{2}

so plug in the numbers

a ^{2}  + 17 {}^{2}  = 15 {}^{2}

then square each of the known numbers to get

a {}^{2}  + 289 = 225

subtract 289 from 225 to get -64

then you are left with

a {}^{2}  =  - 64

then take the square root of -64

to get -8

victus00 [196]3 years ago
3 0

Answer:

a^2 = c^2 - b^2

to get A though you need to take the square root.

Step-by-step explanation:

you need to rearrange the formula to get a by itself.

c^2 = a^2 + b^2

a^2 = c^2 - b^2

to get A though you need to take the square root.

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3. Suppose U= {1,2,3,4,5,6,7,8,9,10} is the universal set and Q= {3,6,9}. What is Q'?
Readme [11.4K]

Answer:

3. Q' = {1 , 2 , 4 , 5 , 7 , 8 , 10} ⇒ answer C

4. A ⊂ B is False ⇒ answer B

Step-by-step explanation:

3.

- The universal set U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10}

- The set Q = {3 , 6 , 9}

- We need to find the complement of set Q (Q')

- The complement set of Q is the set of all elements belongs to the

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- That means take off all the elements belongs to set Q from the

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∵ U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10}

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4.

- The universal set U = {1 , 2 , 3 , 4 , 5 , 6 , 7 , 8}

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- The set B= {4 , 5 , 6}

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∵ A= {1 , 3 , 5 , 7}

∵ B= {4 , 5 , 6}

∵ The elements in set A ∉ in set B

∴ A ⊂ B is False

7 0
3 years ago
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