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3 years ago

36. Write the triangle congruence criterion illustrated by each pair of triangles.

Mathematics

1 answer:

insens350 [35]3 years ago

6 0

Answer:

A - ASA

B - ASA

C - SAS

D - SSS

Step-by-step explanation:

I hope this helps you out!

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Solve the equation: 8y - 3 = бу + 17

balandron [24]

Hey!

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Steps To Solve:

8y - 3 = бу + 17

~Subtract 8y to both sides

8y - 3 - 8y = бу + 17 - 8y

~Simplify

-3 = -2y + 17

~Subtract 17 to both sides

-3 - 17 = -2y + 17 - 17

~Simplify

-20 = -2y

~Divide -2 to both sides

-20/-2 = -2y/-2

~Simplify

10 = y

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Hence, the answer is $\Large\boxed{\mathsf{y~=~10}}$

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Hope This Helped! Good Luck!

3 0

2 years ago

Read 2 more answers

i need help asap!! Which of the following statements is false? Most absolute value equations will yield two different solutions.

Bezzdna [24]

the false statement is: the absolute value of a number can be negative.

the absolute value of a number is never negative

6 0

3 years ago

Which is the graph of y=3/4x-3 Graph A Graph B Graph C.

irina [24]

Answer:

Graph A

Step-by-step explanation:

I had this question in my class and got it right with answer A :')

8 0

3 years ago

Help me asap you guys i need help

Thepotemich [5.8K]

Hi there! :)

Answer:

$\huge\boxed{C}$

To simplify the process, convert each given weight into standard notation:

Lion:

$1 * 10^{5} = 1 * 100000 = 100,000 g$

Ant:

$2 * 10^{-3} = 2* 0.001 = 0.002$

Divide the ant's weight from the lion's weight:

$100000 / 0.002 = 50,000,000$

Convert to scientific notation: (use # of zeros to determine exponent)

$50,000,000 = 5 * 10^{7}$

Therefore, the correct answer is C.

5 0

3 years ago

According to the National Institute on Drug Abuse, a U.S. government agency, 17.3% of 8th graders in 2010 had used marijuana at

miskamm [114]

Answer:

The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.

If the test is done anyway, the null hypothesis failed to be rejected.

The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.

Step-by-step explanation:

The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.

$np=80*0.1=8$

If the test of hypothesis is done as if the conditiones were met, we know that the claim is that the percentage is lower in this district.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.173\\\\H_a:\pi$

The significance level is 0.05.

The sample has a size n=80.

The sample proportion is p=0.1.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578$

This test is a left-tailed test, so the P-value for this test is calculated as:

$P-value=P(z$

As the P-value (0.057) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the percentage is lower in this district.

7 0

3 years ago