1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
love history [14]
3 years ago
6

Explain why silicon dioxide is a suitable material for lining furnaces

Chemistry
1 answer:
zzz [600]3 years ago
3 0
Because it has a really high melting point, i thinks its 1600 to 1725 degrees ferenheight

You might be interested in
How much heat must be removed from 456 g of water at 25.0°c to change it into ice at?
N76 [4]
This question can be simply solved by using heat formula,
    Q = mCΔT

Q = heat energy (J)
m = Mass (kg)
C = Specific heat capacity (J / kg K)
ΔT = Temperature change (K)

when water freezes, it produces ice at 0°C (273 K)
hence the temperature change is 25 K (298 K - 273 K)
C for water is 4186 J / kg K or 4.186 J / g K
By applying the equation,
 Q = 456 g x 4.186 J / g K x 25 K
     = 47720.4 J
     = 47.72 kJ

hence 47.72 kJ of heat energy should be removed.
5 0
3 years ago
Inertia increases as an object's_______increases.
lilavasa [31]

Answer:

<h2><em><u>MASS</u></em></h2>

Explanation:

Inertia increases as an object's <u>Mass</u> increases.

3 0
3 years ago
All of the following require breaking and forming chemical bonds except
skad [1K]
As far as I know, the answer is B (breaking a rock)
3 0
3 years ago
The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t
Sloan [31]

Answer:

Mass =  42.8g

Explanation:

4 NH 3 ( g ) + 5 O 2 ( g ) ⟶ 4 NO ( g ) + 6 H 2 O ( g )

Observe that every 4 mole of ammonia requires 5 moles of oxygen to obtain 4 moles of Nitrogen oxide and 6 moles of water.

Step 1: Determine the balanced chemical equation for the chemical reaction.

The balanced chemical equation is already given.

Step 2: Convert all given information into moles (through the use of molar mass as a conversion factor).

Ammonia = 63.4g × 1mol / 17.031 g = 3.7226mol

Oxygen = 63.4g × 1mol / 32g = 1.9813mol

Step 3: Calculate the mole ratio from the given information. Compare the calculated ratio to the actual ratio.

If all of the 1.9831 moles of oxygen were to be used up, there would need to be 1.9831 × 4 / 5 or 1.5865 moles of Ammonia. We have 3.72226 moles of ammonia - Far excess. Because there is an excess of Ammonia, the Oxygen amount is used to calculate the amount of the products in the reaction.

Step 4: Use the amount of limiting reactant to calculate the amount of H2O produced.

5 moles of O2  = 6 moles of H2O

1.9831 moles = x

x = (1.9831 * 6 ) / 5

x = 2.37972 moles

Mass of H2O = Molar mass * Molar mass

Mass = 2.7972 * 18

Mass =  42.8g

6 0
3 years ago
Under what environmental conditions are you most likely to generate static electricity?
ch4aika [34]
If it is a really humid warm day, have you ever noticed that's when all electrical storms occur
4 0
4 years ago
Other questions:
  • How many moles are in 25.2 grams of HF
    14·1 answer
  • .....m..........m.....mm...​
    6·1 answer
  • a) What is the common-ion effect?b) Given an example of a salt that can decrease the ionization of HNO2 in solution. List all of
    14·1 answer
  • Debscribe each of the following with the correct term
    5·1 answer
  • Identify this reaction
    8·1 answer
  • If an object has a volume of 45 cm^3 what is the volume in ml?
    9·1 answer
  • Scientific law describes what nature does under certain conditions
    14·1 answer
  • Can someone please give me a very simple definition of nuclear fusion make it as simple as possible
    9·1 answer
  • At a certain temperature the vapor pressure of pure acetyl bromide is measured to be . Suppose a solution is prepared by mixing
    10·1 answer
  • True or false.  As a wave travels through a given material its velocity changes.
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!