Answer is: mass od zinc is 392,28 g.
N(Zn) = 3,6·10²⁴.
n(Zn) = N(Zn) ÷ Na.
n(Zn) = 3,6·10²⁴ ÷ 6·10²³ 1/mol.
n(Zn) = 6 mol.
m(Zn) = n(Zn) · M(Zn).
m(Zn) = 6 mol · 65,38 g/mol.
m(Zn) = 392,28 g.
Na - Avogadro number.
n - amount of substance.
M - molar mass.
The investigation using solid and liquid water to show that thermal energy is not the same as temperature is:
- Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.
<h3>What is the response to the experiment above?</h3>
The response is No, because the lake is known to have a lot more particles than the glass of water and so they will not have the same thermal energy.
Note that the temperature is seen as the an average and thermal energy is seen to be the total. A glass of water can be able to have the same temperature as what we call Lake Superior, but the lake has a lot of thermal energy due to the fact that the lake has a lot of water molecules.
So the investigation using solid and liquid water to show that thermal energy is not the same as temperature is Place a glass of water and a lake and both should be at the same temperature, find out if do they have the same amount of total thermal energy.
Learn more about thermal energy from
brainly.com/question/19666326
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Both carbon and lead belong to Group IV elements, and thus they have the same number of valence electrons.
<span>In
each of the other options, the two elements belong to different groups,
and thus they do NOT have the same number of valence electrons.
I hope this helped you, please tell me if I am correct or not <3
</span>
Answer:
94.325 g
Explanation:
We'll begin by converting 350 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
350 mL = 350 mL × 1 L /1000 mL
350 mL = 0.35 L
Next, we shall determine the number of mole of KC₂H₃O₂ in the solution. This can be obtained as follow:
Volume = 0.35 L
Molarity of KC₂H₃O₂ = 2.75 M
Mole of KC₂H₃O₂ =?
Molarity = mole /Volume
2.75 = Mole of KC₂H₃O₂ / 0.35
Cross multiply
Mole of KC₂H₃O₂ = 2.75 × 0.35
Mole of KC₂H₃O₂ = 0.9625 mole
Finally, we shall determine the mass of KC₂H₃O₂ needed to prepare the solution. This can be obtained as illustrated below:
Mole of KC₂H₃O₂ = 0.9625 mole
Molar mass of KC₂H₃O₂ = 39 + (12×2) +(3×1) + (16×2)
= 39 + 24 + 3 + 32
= 98 g/mol
Mass of KC₂H₃O₂ =?
Mass = mole × molar mass
Mass of KC₂H₃O₂ = 0.9625 × 98
Mass of KC₂H₃O₂ = 94.325 g
Thus, the mass of KC₂H₃O₂ needed to prepare the solution is 94.325 g
Answer:
i would or i have or i did
Explanation:
